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Thepotemich [5.8K]
3 years ago
9

The age distribution of students at a community college is given below. Age (years) Number of students (f) Under 21 2890 21-24 2

190 25-28 1276 29-32 651 33-36 274 37-40 117 Over 40 185 A student from the community college is selected at random. The events A and B are defined as follows. A = event the student is at most 32 B = event the student is at least 37 Are the events A and B disjoint? No Yes
Mathematics
1 answer:
Soloha48 [4]3 years ago
3 0

Answer:

Are the events A and B disjoint? Yes

Step-by-step explanation:

Disjoint events are those events that cannot occur at the same time, i.e. for events <em>X</em> and <em>Y</em> to be disjoint, P(X\cap Y)=0.

The event <em>A</em> is defined as the number of students whose age is at most 32.

And event <em>B</em> is defined as the number of students whose age is at least 37.

The events <em>A</em> and <em>B</em> are disjoint events.

  • The sample space for event <em>A</em> consists of all the students of age group (under 21), (21 - 24), (25 - 28) and (29 - 32).
  • Whereas the sample space for event <em>B</em> consists of all the students of age group (33 - 36), (37 - 40) and (Over 40).

The sample space for the intersection of these two events is:

Sample space of (<em>A</em> ∩ <em>B</em>) = 0

As there are no common terms in both the sample.

Hence proved, events <em>A </em> and <em>B</em> are disjoint.

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Question:

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Step-by-step explanation:

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\frac{-3}{5} / \frac{5}{3} = \frac{-3}{5} * \frac{5}{3} = \frac{-15}{15} = -1

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