Since the grade of the numerator and the denominator is the same, then the limit exists and is distinct from 0. The limit of the expression is 4/7.
<h3>How to determine the limit of a rational expression when x tends to infinite</h3>
In this problem we must apply some algebraic handling and some known limits to determine whether the limit exists or not. The limit exists if and only if the result exists.
4/7
Since the grade of the numerator and the denominator is the same, then the limit exists and is distinct from 0. The limit of the expression is 4/7.
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Answer:
10th term is 10
Step-by-step explanation:
The nth term for finding the geometric progression is expressed as;
Tn = ar^n-1
a is the first term
r is the common ratio
n is the number of terms
a11 = ar^11-1
a11 = ar^10
Since a11 = -5 and r = -1/2
-5 = a(-1/2)^10
-5 = a(1/1024)
a= 1024 * -5
a = -5120
Nest is to get the 10th terms
a10 = ar^9
a10 = -5120 * (-1/2)^9
a10 = -5120 * -1/512
a10 = 10
Hence the 10th term of the sequence is 10
Answer
the area is 26 cm
Step-by-step explanation:
for the first part well call it box C box c is 2 cm by 1 cm the area of that box is 2 because 2 x 1 =2
for box B which is 2 cm by 6 cm because you add the 3 on the bottom to the 3 on the top so box B = 12
for box A it is 3 by 4 so that would be 12
you add the results together 12+12+2=26cm
They are equal, 8 x 7 = 56 and 7 x 7 = 49
Answer:
7.7 ft
Step-by-step explanation:
The third longest side is also the second shortest side.
The 14 ft side of quadrilateral ABCD corresponds to the 6 ft side of quadrilateral EFGH.
14/6 = 18/x
7/3 = 18/x
7x = 18 * 3
7x = 54
x = 54/7
x = 7.7
Answer: D. 7.7 feet
