Answer:
=========================
<h2>Given </h2>
Triangle with:
- Base of n² -3,
- Midsegment of 39.
<h2>To find</h2>
<h2>Solution</h2>
As per definition of midsegment, it is connecting the midpoints of two sides and its length is half the length of the opposite side of the triangle.
So we have:
Solve it for n:
- n² - 3 = 78
- n² = 81
- n = √81
- n = 9
Correct choice is D.
We know that
360°/12 hour-----------> 30°/hour
<span>Central angle at 4 .00 is 120 degrees
the radius of a clock is 6/2-----> r=3 in
length of a circumference=2*pi*r-----> 2*pi*3----> 18.84 in
the minor arc at 4 .00 is for a central angle of 120</span>°
so
if 360° (full circle)---------> has a length of 18.84 in
120°----------------------> X
X=120*18.84/360-------> X=6.28 in
the answer is
6.28 in
Well when you add $84+$29 you get $113
1/a^3
The guy above me is probably also right
