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Mazyrski [523]
2 years ago
8

Choose the equation of a circle with radius 6 and center (2, -3).

Mathematics
1 answer:
Rufina [12.5K]2 years ago
3 0

Answer:  (x-2)^2 + (y+3)^2 = 36\\\\

Work Shown:

(x-h)^2 + (y-k)^2 = r^2\\\\(x-2)^2 + (y-(-3))^2 = 6^2\\\\(x-2)^2 + (y+3)^2 = 36\\\\

Note that (h,k) = (2,-3) is the center and r = 6 is the radius. The last line is not expanded out using the FOIL rule because its common practice to leave it in (x-h)^2 + (y-k)^2 = r^2\\\\ form. This form allows the reader to quickly determine the center and radius (rather than have to do a lot of algebraic steps before hand).

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A car travels at a speed of 41 meters/second using 756 joules of energy every second. Suppose we know that the car uses 52,700 j
Oksana_A [137]

Answer: 2858.11 meters  

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

Total energy =52,700 joules

Energy per second = 756 joules

Time = joules / (joules / sec) =52,700/756 =69.71 sec

Now, to find the distance:

Distance = speed rate x time

d = 41 meters/second x 69.71 sec = 2858.11 meters  

Feel free to ask for more if needed or if you did not understand something.  

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Number 14 only. Please I really need help on this.
Zigmanuir [339]

rate of change is the distance divided by minute or whatever measurment your using that changes

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Which measurements would be correct for trapezoid EFGH if it were similar to trapezoids ABCD?
grandymaker [24]
<span>C side EF=18 cm; side GH = 30 ; height = 6 cm </span>
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3 years ago
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Can you help me with my math questions
GrogVix [38]

p^2+2(7)p+7^2=(p+7)^2


Justification:

Given:  p^2+14p+49


Split the middle term;

=p^2+7p+7p+49


Factor:

=p(p+7)+7(p+7)


=(p+7)(p+7)


=(p+7)^2


QUESTION 3a

The given expression for the area of the rectangle is  36x^2-12x+1.


This is equal to the indicated area which is 289\;in^2


This implies that


36x^2-12x+1=289


\Rightarrow (6x-1)^2=289


\Rightarrow (6x-1)(6x-1)=289


\Rightarrow l=(6x-1),w=(6x-1)



This implies that, the dimensions of the rectangle are equal;


Using the square root method, we obtain

\Rightarrow (6x-1)=\pm \sqrt{289}


\Rightarrow (6x-1)=\pm 17


\Rightarrow 6x=1\pm 17


\Rightarrow 6x=18 \:or\:6x=-16


\Rightarrow x=3 \:or\:x=-\frac{2}{3}

We discard the negative value.

The side length of this rectangle is


\Rightarrow l=(6(3)-1)=17,w=6(3)-1=17


QUESTION 3b

The given expression for the area of the rectangle is  25x^2-50x+25.


This is equal to the indicated area which is 1225\;in^2


This implies that


25x^2-50x+25=1225


25(x^2-2x+1)=1225


(5(x-1))^2=35^2


5(x-1)5(x-1)=49


\Rightarrow l=5(x-1),w=5(x-1)



This implies that, the dimensions of the rectangle are equal;


Using the square root method, we obtain

\Rightarrow 5(x-1)=\pm \sqrt{1225}


\Rightarrow 5(x-1)=\pm 35


\Rightarrow x=1\pm 7


\Rightarrow x=8 \:or\:x=-6

We discard the negative value.

The side length of this rectangle is


\Rightarrow l=5(8-1)=35,w=5(8-1)=35



QUESTION 3c

The given expression for the area of the rectangle is  49x^2-56x+16.


This is equal to the indicated area which is 289\;in^2


This implies that


49x^2-56x+16=289




(7x-4)^2=289


(7x-4)(7x-4)=289



\Rightarrow l=(7x-4),w=(7x-4)


Applying the laws of indices gives;


(7x-4)^2=17^2


This implies that;

7x-4=17


7x=21


x=3in.


The side length of this rectangle is


\Rightarrow l=7(3)-4=17\:in.,w=7(3)-4=17\:in.


Dont forget that the square is also a rectangle.





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