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Mazyrski [523]
2 years ago
8

Choose the equation of a circle with radius 6 and center (2, -3).

Mathematics
1 answer:
Rufina [12.5K]2 years ago
3 0

Answer:  (x-2)^2 + (y+3)^2 = 36\\\\

Work Shown:

(x-h)^2 + (y-k)^2 = r^2\\\\(x-2)^2 + (y-(-3))^2 = 6^2\\\\(x-2)^2 + (y+3)^2 = 36\\\\

Note that (h,k) = (2,-3) is the center and r = 6 is the radius. The last line is not expanded out using the FOIL rule because its common practice to leave it in (x-h)^2 + (y-k)^2 = r^2\\\\ form. This form allows the reader to quickly determine the center and radius (rather than have to do a lot of algebraic steps before hand).

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