3 years ago

Chris is painting a wall with a length of 3 meters and a width of 1.6 meters

Mathematics

1 answer:

neonofarm [45]3 years ago

4 0

Ok, so...what is the question?...

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Solve the inequality 5p -3 < 7 + 3p for p

KiRa [710]

Step-by-step explanation:

p<5 that's the answer for the question

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2 years ago

A triangle has sides with lengths of 4 inches, 14 inches, and 17 inches. Is it a right triangle?

irga5000 [103]

Yes it is because 2 sides would be the legs while 1 side is the hyptonuese so in this case 4 is a leg and 14 and 17 is the hyptonuese

5 0

2 years ago

the question is in the picture below, if you could show all your work so i can see how to do it, that would be appreciated.

ki77a [65]

m∠R = 27.03°

Solution:

Given In ΔQRP, p = 28 km, q = 17 km, r = 15 km

To find the measure of angle R:

Law of cosine formula for ΔQRP:

$r^{2}=p^{2}+q^{2}-2 pq \cos R$

Substitute the given values in the above formula.

$(15)^{2}=(28)^{2}+(17)^{2}-2 (28)(17) \cos R$

$225=784+289-952 \cos R$

$225=1073-952 \cos R$

Switch the given equation.

$1073-952 \cos R=225$

Subtract 1073 from both side of the equation.

$-952 \cos R=-848$

Divide by –952 on both sides.

$$ \cos R=\frac{106}{119}$

$$ R=\cos^{-1} \left(\frac{106}{119}\right)$

$R=27.03^\circ$

Hence m∠R = 27.03°.

7 0

3 years ago

What is the approximate solution to this equation?

Sindrei [870]

Answer: b)

Step-by-step explanation:

3^3 is equal to 27 exactly, but it asks for an approximate. 27.55 is near 27 so yea, there ya go ^

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3 years ago

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A 16 N force is applied to an object and 96 J of work is done. How far was the object moved?

Montano1993 [528]

Hello,

T=F*x==>x=T/F=96/16=6 (m)

T is the word (travail in french)
F is the force applied
x is the deplacement.

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3 years ago

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