line J passes through points (-6,1) and (-3,6) . Line m is parallel to line j and passes through point (15,-1).what is the equat
ion of line m ?
1 answer:
Slope of the line J
(6-1) / (-3-(-6))
5 / 3
so
m = 5/3
If this line passes through (15,-1)
y = mx + c
-1 = (5/3)*15 + c
-1 = 25 + c
c = -26
equation is
y = (5/3)x - 26
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