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lbvjy [14]
3 years ago
6

Which expressions are differences of squares? Select each correct answer

Mathematics
2 answers:
garri49 [273]3 years ago
4 0
For this ones the second value is always negative so A is not correct. Also they have to have an exact square root which 50 doesn't. So the answers are B and C
(a-6)(a+6)
(w-11)(w+11)
murzikaleks [220]3 years ago
4 0

Answer:

Option B, C and D are correct.

a^2-36, w^2-121 and n^2-50

Step-by-step explanation:

For any real number a and b:

Difference of square is given by:

a^2-b^2 = (a-b)(a+b)

We have to find Which expressions are differences of squares.

Option A :

x^2+25

⇒x^2+5^2

This cannot be written as a difference of square.

Option B:

a^2-36

⇒a^2-6^2

⇒(a-6)(a+6)

Option C:

w^2-121

⇒w^2-11^2

⇒(w-11)(w+11)

Option D:

n^2-50

⇒n^2-(\sqrt{50})^2

⇒(n-\sqrt{50})(n+\sqrt{50})

Therefore, the expressions which are are differences of squares are:

a^2-36, w^2-121 and n^2-50

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The long jump distances of four students are listed in the table below. How much farther
Papessa [141]
I can’t answer this with out the distance they jumped.
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=4%20%20%20%7B%7D%5E%7Bx%20%7D%20%20%2B%206%20%7B%7D%5E%7Bx%7D%20%3D%209%20%7B%7D%5E%7Bx%7D%20%
Nookie1986 [14]

So, the value of x is 1.19

The question is an exponential equation

<h3>What is an exponential equation?</h3>

An exponential equation is a mathematical expression between two quantities in which one variable is raised to a power of the other variable.

<h3>How to find x?</h3>

Since 4^{x} + 6^{x} = 9^{x},

Dividing through by 4ˣ, we have

\frac{4^{x} }{4^{x} } + \frac{6^{x} }{4^{x} }  = \frac{9^{x} }{4^{x} } \\1 + (\frac{6}{4})^{x} }  = (\frac{9}{4})^{x} } \\1 + (\frac{3}{2})^{x} }  = (\frac{3^{2} }{2^{2} })^{x} } \\1 + (\frac{3}{2})^{x} }  = (\frac{3}{2})^{2x} }

Let y = (3/2)ˣ

So,

1 + y = y²

y² - y - 1 = 0

Using the quadratic formula to find y,

y = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}

where a = 1 b = -1 and c = -1

Substituting the values of the variables into the equation, we have

y = \frac{-(-1) +/- \sqrt{(-1)^{2} - 4\times 1 \times (-1)} }{2\times 1}\\= \frac{1 +/- \sqrt{1 + 4} }{2}\\= \frac{1 +/- \sqrt{5} }{2}\\= \frac{1 - \sqrt{5} }{2} or  \frac{1 + \sqrt{5} }{2}\\= \frac{1 - 2.236}{2} or  \frac{1 + 2.236}{2}\\= \frac{- 1.236}{2} or  \frac{3.236}{2}\\= -0.618 or 1.618

Since y = (3/2)ˣ

Takung logarithm of both sides, we have

㏒y = ㏒(3/2)ˣ

㏒y = x㏒(3/2)

x = ㏒y/㏒(3/2)

x = ㏒y/㏒1.5

Since we do not have logarithm of a negative number, we use y = 1.618.

So, x = ㏒y/㏒1.5

x = ㏒1.618/㏒1.5

x = 0.2090/0.1761

x = 1.19

So, the value of x is 1.19

Learn more about exponential equation here:

brainly.com/question/11832081

#SPJ1

5 0
1 year ago
For the situation, write and solve an equation. Then, explain what your solution means. If you get stuck, try drawing a diagram
Bess [88]

Answer:

5r + (5 x 6) = 84

looking for rice per pound.

Step-by-step explanation:

5r + (5 x 6)  = 84

This shows an equation where we need to make r the subject to establish how many pounds a bag of rice weighs.

5r + (5 x 6)  = 84

5r + (30)  = 84

5r = 84-30

5r = 54/5

r  = 10 4/5  

r  =  10.8 pounds

5 0
3 years ago
Read 2 more answers
Brainliest if its right
ira [324]

Formula : C=2πr

43.98

4 0
2 years ago
Read 2 more answers
PLEASE HELP !!
Pavlova-9 [17]
Log 10  100 =2
Basically, we have to know how to solve for x in this equation:
10^x = 100

For log3 = 9 we have to solve for x in this equation:
3^x = 9
Therefore, x = 2


6 0
3 years ago
Read 2 more answers
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