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docker41 [41]
2 years ago
13

Find the equation of a line perpendicular to y= 3x + 7 that passes through the point (9,-7).

Mathematics
2 answers:
liraira [26]2 years ago
7 0
Okay so the gradient of the perpendicular line is -1/3 and then from there u have to solve for the y intercept. Substitute in 9 and -7 where -7 is y and 9 is x. The equation is y=-1/3x-4 :)
levacccp [35]2 years ago
7 0

Answer:

y=-\frac{1}{3}x-4

Step-by-step explanation:

To find the slope perpendicular to this, take the negative reciprocal of the slope. Basically, invert both the fraction and the negative/positive so that 3 becomes -1/3.

Now, using the new slope and the given point, we can find the y-intercept. Plug the 3 known variables into the equation:

y=mx+b\\-7=(-\frac{1}{3})(9)+b

Then, solve for b:

-7=-3+b\\-4=b\\b=-4\\

Finally, with both the slope and the y-intercept, you can write the equation of the line:

y=-\frac{1}{3}x-4

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