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docker41 [41]
2 years ago
13

Find the equation of a line perpendicular to y= 3x + 7 that passes through the point (9,-7).

Mathematics
2 answers:
liraira [26]2 years ago
7 0
Okay so the gradient of the perpendicular line is -1/3 and then from there u have to solve for the y intercept. Substitute in 9 and -7 where -7 is y and 9 is x. The equation is y=-1/3x-4 :)
levacccp [35]2 years ago
7 0

Answer:

y=-\frac{1}{3}x-4

Step-by-step explanation:

To find the slope perpendicular to this, take the negative reciprocal of the slope. Basically, invert both the fraction and the negative/positive so that 3 becomes -1/3.

Now, using the new slope and the given point, we can find the y-intercept. Plug the 3 known variables into the equation:

y=mx+b\\-7=(-\frac{1}{3})(9)+b

Then, solve for b:

-7=-3+b\\-4=b\\b=-4\\

Finally, with both the slope and the y-intercept, you can write the equation of the line:

y=-\frac{1}{3}x-4

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8 0
3 years ago
The two cones are congruent. Determine the unknown measures of the cones. A = units B = units C = units D = units
VikaD [51]

Answer:

3.1

4.2

5.2

42

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Can anyone help me with Question 7? I’m not good at word problems :(
romanna [79]
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7 0
3 years ago
F(x)= 5x^2+6, g(x)= 7x find (f o g)(x), find (g o f)(x), find f(g(-4)), fine g(f(5))
KiRa [710]

(f o g)(x) = 245x^2+6\\(g o f)(x) = 5x^2+42\\ f(g(-4)) = 3926\\g(f(5)) = 917

Step-by-step explanation:

Given

f(x) = 5x^2+6\\g(x) = 7x

So

(f o g)(x) = 5(7x)^2+6\\= 5(49x^2)+6\\=245x^2+6\\(g o f)(x) = 7(5x^2+6)\\= 35x^2+42\\(fog(x))=245x^2+6f(g(-4)) = 245(-4)^2+6 \\=245(16)+6\\=3920+6\\=3926\\g(f(x)) = 35x^2+42\\g(f(5)) = 35(5)^2+42\\=35(25)+42\\=875+42\\=917

Hence,

(f o g)(x) = 245x^2+6\\(g o f)(x) = 5x^2+42\\ f(g(-4)) = 3926\\g(f(5)) = 917

Keywords: functions, Function composition

Learn more about functions at:

  • brainly.com/question/4279146
  • brainly.com/question/4354581

#LearnwithBrainly

7 0
3 years ago
Help with these please
JulsSmile [24]
Do you want the answer?
4 0
3 years ago
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