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4 years ago

What is the weight per cm?

Mathematics

2 answers:

lubasha [3.4K]4 years ago

6 0

Your answer will be 2/5 g/cm it is correct ✨

Dmitry [639]4 years ago

5 0

Answer:

2/5 g/cm

Step-by-step explanation:

When you want to know "A per B", divide the given quantity of A by the corresponding quantity of B. ("Per" essentially means "divided by".)

It can be convenient to choose table values that make the division easy:

12 g/(30 cm) = 4/10 g/cm = 0.4 g/cm

20 g/(50 cm) = 2/5 g/cm . . . . . . . . . . . . . same as 0.4 g/cm

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20.9 cm^3

Step-by-step explanation:

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3 years ago

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The secretary in Exercises 2.121 and 3.16 was given n computer passwords and tries the passwords at random. Exactly one of the p

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Answer:

There is a $\frac{(n-1)^{5}}{n^{6}}$ probability that the correct password is found on the sixth try.

Step-by-step explanation:

We have n passwords, only 1 is correct.

So,

Since a password is put back with other, at each try, we have that:

The probability that a password is correct is $\frac{1}{n}$

The probability that a password is incorrect is $\frac{n-1}{n}$ .

There are 6 tries.

We want the first five to be wrong. So each one of the first five tries has a probability of $\frac{n-1}{n}$ . So, for the first five tries, the probability of getting the desired outcome is $\frac{(n-1)^{5}}{n^{5}}$ .

We want to get it right at the sixth try. The probability of sixth try being correct is $\frac{1}{n}$ .

So, the probability that the first five tries are wrong AND the sixth is correct is:

$P = \frac{(n-1)^{5}}{n^{5}}\frac{1}{n} = \frac{(n-1)^{5}}{n^{6}}$

There is a $\frac{(n-1)^{5}}{n^{6}}$ probability that the correct password is found on the sixth try.

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3 years ago

1.3. If Sara draws a red ball and DOES NOT RETURN it, and then she goes to draw a green

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Answer:

Dependent Event

Step-by-step explanation:

Assume that are 10 balls, such that:

$Red = 6$

$Green = 4$

If the balls are replaced after taken, the probability is:

$Pr(Red) = 6/10$

$Pr(Green) = 4/10$

This is referred to as independent event; because each selection do not affect the next or previous selection

However, if the balls are not replaced, the probability is:

$Pr(Red) = 6/10$

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We subtracted 1 because there is a reduction in the number of balls when the red ball is not returned.

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3 years ago

Find the minimum sample size necessary to be 99% confident that the population mean is within 3 units of the sample mean given t

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Answer:

The minimum sample size required is 207.

Step-by-step explanation:

The (1 - α) % confidence interval for population mean μ is:

$CI=\bar x\pm z_{\alpha /2}\frac{\sigma}{\sqrt{n}}$

The margin of error of this confidence interval is:

$MOE=z_{\alpha /2}\frac{\sigma}{\sqrt{n}}$

Given:

$MOE=3\\\sigma=29\\z_{\alpha /2}=z_{0.01/2}=z_{0.05}=2.576$

*Use a z-table for the critical value.

Compute the value of n as follows:

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Thus, the minimum sample size required is 207.

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3 years ago

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4 years ago

What is the weight per cm? ​

What is the weight per cm?