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grandymaker [24]
3 years ago
11

Explain how to solve the equation 9=q-4

Mathematics
2 answers:
castortr0y [4]3 years ago
4 0

add them both then you get the awnser if the four is not a negative. if the four is a negative use division.

OlgaM077 [116]3 years ago
3 0
Q= 9+4
q= 13

its simple, the numbers are just in a different order, but you have look carefully. hope this helped :)
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A square of side lengths 5 cm. find its diagonal length​
kramer

Answer:

7.07107cm

Step-by-step explanation:

d= \sqrt{2} a =\sqrt{2} (5) = 7.07107

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Mrs. Rodrigues was seling two kinds of raffle tickets for $1.50 and $3.50. The number of 1.50 tickets sold was 5 more than three
disa [49]

Step-by-step explanation:

पति ऑफिस से घर आया... और खाना खाने बैठा

खाते-खाते उसने अपनी पत्नी से कहा कि

"खाना ठीक नहीं है, कोई टेस्ट नहीं आ रहा है।"

पत्नी चुपचाप उठी, और उसने कॉरपोरेशन मेंं कॉल किया और एम्बुलेंस को बुला ली

और कहा..

"इन्हे टेस्ट नहीं आ रहा है.."

एम्बुलेंस पति को ले गयी और उसे क्वॉरंटाइन कर दिया

अस्पताल में पत्नी ने पति को फोन किया और पूछा: अब आया स्वाद??

यहाँ तक की कहानी सबने सुनी होगी। अब देखिये कहानी में नया मोड़:

⬇️

.

.

.

.

.

.

.

.

उधर पति को पूछा गया कि

"आपके संपर्क में कौन-कौन आया था ?"

पति ने बड़ी ही शांति से कहा..

- मेरी पत्नी

- मेरा ससुर

- मेरी सास

- मेरा साला

- मेरी साली

बस अब ये सब भी अस्पताल के बिस्तर पर बैठे-बैठे पति को घूर रहे हैं!

Moral of the story is

बेजुबान को ज्यादा सताना भी ठीक

5 0
3 years ago
Read 2 more answers
Find the missing values on the diagram below. Assume that each line is evenly divided. I'm pretty confused on the right side of
belka [17]

Answer:

A = 72 B = 50% C = 40%

Step-by-step explanation:

Each space on the bottom is worth 10%.

Each space on the bottom is worth 36.

7 0
3 years ago
A population of monkeys' tail lengths is normally distributed with a mean of 25 cm with a standard deviation of 8 cm. I am prepa
Crank

Answer:

<em>The probability that the mean of my sample will be between 24 and 25 cm</em>

<em>P(24 ≤X⁻≤25) = 0.4772</em>

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

<em>Given mean of the Population  'μ'= 25c.m</em>

<em>Given standard deviation of the Population 'σ' = 8c.m</em>

<em>Given sample size 'n' = 256</em>

<em>Let X₁ = 24</em>

<em></em>Z_{1}  = \frac{x_{1}-mean }{\frac{S.D}{\sqrt{n} } } = \frac{24-25}{\frac{8}{\sqrt{256} } } =  -2<em></em>

<em>Let X₂ = 25</em>

<em></em>Z_{2}  = \frac{x_{2}-mean }{\frac{S.D}{\sqrt{n} } } = \frac{25-25}{\frac{8}{\sqrt{256} } } = 0<em></em>

<u><em>Step(ii)</em></u><em>:-</em>

<em>The probability that the mean of my sample will be between 24 and 25 cm</em>

<em>P(24 ≤X⁻≤25) = P(-2≤ Z ≤0)</em>

                     = P( Z≤0) - P(Z≤-2)

                     = 0.5 + A(0) - (0.5- A(-2))

                     = A(0) + A(2)        ( ∵A(-2) =A(2)

                     = 0.000+ 0.4772

                     = 0.4772

<u><em>Final answer</em></u>:-

<em>The probability that the mean of my sample will be between 24 and 25 cm</em>

<em>P(24 ≤X⁻≤25) = 0.4772</em>

                     

4 0
3 years ago
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