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Svetradugi [14.3K]
3 years ago
10

Item 6

Mathematics
1 answer:
Sedbober [7]3 years ago
7 0
To find the diameter of the circle it’s C=(2)(3.14)(r) radius is 8/2 which is 4 so 2(3.14)(4) is 25.13 + 36 is 61.13

The perimeter of the whole figure is 61.13in^2
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The answer to this is 62. 
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What is the unit rate of 2.99 for 14 pounds
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It is .21 or 21 cents for each pound.
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X-y&lt;3<br> Do I need to flip the sign?
Scilla [17]
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4 years ago
The following function describes the number of employees working at a company, In thousands, where trepresents the number of yea
NISA [10]

Consider the missing part of the question is "Select the correct statement.

A. The number of employees is increasing by 50% every year.

B. The number of employees is decreasing by 10% every year.

C. The number of employees is decreasing by 90% every year.

D. The number of employees is increasing by 90% every year."

Given:

The function is:

f(t)=1.5(0.90)^t

Where, f(t) is the number of employees working at a company, in thousands and t is the number of years since the company revised the benefits package.

To find:

The correct statement from the given options.

Solution:

The general exponential decay model is:

f(t)=a(1-r)^t         ...(i)

Where, a is the initial value, r is the rate of decay and t is the number of years.

We have,

f(t)=1.5(0.90)^t

It can be written as

f(t)=1.5(1-0.10)^t        ...(ii)

From (i) and (ii), we get

a=1.5,r=0.10

The initial value is 1.5 and the rate of decay is 0.10 or 10%. It means the number of employees is decreasing by 10% every year.

Therefore, the correct option is B.

5 0
3 years ago
What is the slope of the line that passes through the points (6-8) and (10,-8)?
romanna [79]

Answer:

The slope of the line that passes through the points would be 0

Step-by-step explanation:

Lets use the formula : y2-y1/x2-x1

In this case lets let y2 be -8 and y1 be -8

And lets let x2 be 6 and x1 be 10, that would look like..

-8-(-8)/6-10

which equals...

0/-4 = 0

We know that the slope of the line is 0

3 0
2 years ago
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