All categories

3 years ago

Mrs.Hense sells a roll of coastal bermuda horse hay for $58. She says she will make $174 if she sells 3 rolls

Mathematics

2 answers:

viktelen [127]3 years ago

8 0

She is correct because 58+58+58=174<span />

vaieri [72.5K]3 years ago

4 0

Yes she will make $174 dollars. Each roll is $58 dollars. You take 58 and multiply it by 3 .
58x3= 174.

You might be interested in

Will mark brainliest<br> please help me asap on this word problem! explain.

Setler79 [48]

Answer:

The second one for both a and b.

Step-by-step explanation:

The first cereal box is:

8•3•11=264 inches cubed

the second cereal box is:

10•10•3=300 inches cubed

a. The box that holds more cereal would be the second one, since it has more volume.

b. The box that requires more material to make is the second one, since the it is bigger in volume, therefore, bigger in length and width.

3 0

3 years ago

Solve the equation 3 x 2 - 5x + 1 = 0 expressing your answer correct to two decimal places

marta [7]

Answer: x = 1.4

Step-by-step explanation:

Simplify:

6-5x+1 = 0

Subtract 1 from both sides:

6 -5x = -1

Subtract 6 from both sides:

-5x = -7

Divide both sides by -5:

x = 1.4

3 0

3 years ago

1. Factor 3h2 - 11h - 42 completely.

Nuetrik [128]

Answer:

3h² - 11h - 42 = (3x+7)(x−6)

Step-by-step explanation:

We need to find factors of 3h² - 11h - 42. It is a quadratic equation.

We search two numbers such that their product is 42 and sum is 11. So,

3h² - 11h - 42 = 3h² -18x +7x -42

= (3x+7)(x−6)

So, the required factors are (3x+7)(x−6).

7 0

3 years ago

Is anyone available to help me out with this problem?

AysviL [449]

Answer:

A'= (0,4)

B'= (-1,2)

C'= (2,1)

D'= (2,3)

Step-by-step explanation:

Hope that this helps! :)

4 0

3 years ago

I need help solving for x: log x = 2.46 - 1.12 * log y

Mariulka [41]

$\bf log_{{ a}}(xy)\implies log_{{ a}}(x)+log_{{ a}}(y)
\\\\\\
% Logarithm of exponentials
log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)
\\\\\\
{{ a}}^{log_{{ a}}x}=x\impliedby \textit{log cancellation rule}\\\\
-----------------------------\\\\$

$\bf log(x)=2.46-1.12log(y)\iff log_{10}(x)=2.46-1.12log_{10}(y)
\\\\\\
log_{10}(x)=2.46-log_{10}(y^{1.12})\implies log_{10}(x)+log_{10}(y^{1.12})=2.46
\\\\\\
log_{10}(x\cdot y^{1.12})=2.46\implies 10^{\cfrac{}{}log_{10}(x\cdot y^{1.12})}=10^{2.46}
\\\\\\
xy^{1.12}=10^{2.46}\implies \boxed{x=\cfrac{10^{2.46}}{y^{1.12}}}$

8 0

4 years ago