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3 years ago

Choose a number line to model the following situation:

Mathematics

2 answers:

katrin2010 [14]3 years ago

7 0

It is the first one because if u gain an amount and lose that same amount you don't gain anything.
25-25=0

babunello [35]3 years ago

5 0

Answer:

First number line.

Step-by-step explanation:

Given : After a gain of 25 yards, the football team lost 25 yards on the next play.

To find : Choose a number line to model the following situation:

Solution : We have given

gain of 25 yards, the football team lost 25 yards on the next play.

We use positive value for gain = + 25.

We use positive value for lost = - 25.

In the number line First we go to 0 to 25 to right and then come back 25 to 0 to left then , we will reach again at 0.

+25 - 25 = 0.

First number line represent the situation .

Therefore, First number line.

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Find the quotient. -1/5 divided by 1 2/8

Serjik [45]

Answer:

-4/25

Step-by-step explanation:

-1/5 ÷ 1 2/8

-1/5 ÷ 10/8

-1/5 ÷ 5/4

-1/5 * 4/5

-4/25

Best of Luck!

5 0

3 years ago

The sides of a triangular plot are in the ratio 3 : 5 : 7 and its perimeter is 300 m. find its area

STALIN [3.7K]

Given :

The sides of a triangular plot are in the ratio 3 : 5 : 7 .
Its perimeter is 300 m.

⠀

To Find :

Its area.

⠀

Solution :

Let us assume the sides in metres be 3x, 5x and 7x .

⠀

Then, We know,

$\qquad \sf \dashrightarrow \: 3x + 5x + 7x = 300 \: \: \: \: \: \: \: Perimeter_{(Triangle)}$

$\qquad \sf \dashrightarrow \: 15x = 300$

$\qquad \sf \dashrightarrow \: x = \dfrac{300}{15}$

$\qquad \bf\dashrightarrow \: x = 20$

⠀

So, The sides of the triangle are :

$\qquad \sf \dashrightarrow \: 3 \times 20 \: m = \bf60 \: m$

$\qquad \sf \dashrightarrow \: 5 \times 20 \: m = \bf 100 \: m$

$\qquad \sf \dashrightarrow \: 7 \times 20 \: m = \bf140 \: m$

⠀

Now, Using Heron's formula :

We have,

$\qquad \sf \dashrightarrow \: s = ( {60 + 100 + 140}) \: m = 300 \: m$

$\qquad \sf \dashrightarrow \: s = \dfrac {60 + 100 + 140}2 \: m = 150 \: m$

⠀

And the Area will be :

$\qquad \sf \dashrightarrow \: \sqrt{150(150 - 60)(150 - 100)(150 - 140)} \: {m}^{2}$

$\qquad \sf \dashrightarrow \: \sqrt{150 \times 90 \times 50 \times 10} \: \: {m}^{2}$

$\qquad \sf \dashrightarrow \: 1500 \sqrt{3} \: {m}^{2}$

8 0

2 years ago

Read 2 more answers

Initially, a population of rabbits was found to contain 192 rabbits. It was estimated that the population was growing exponentia

aleksley [76]

Answer:

the population after 52 days is $34,804.27

Step-by-step explanation:

Given that

There is a population of the rabbits i.e. 192

And, the growth rate is 10%

We need to find out the population after 52 days

So,

= 192 × e^(0.10 × 52)

= $34,804.27

hence, the population after 52 days is $34,804.27

7 0

3 years ago

PLEASE HELP WITH THIS MATH

s2008m [1.1K]

-5 because u subtract them both and they equal it ha

4 0

3 years ago

A self-serve frozen yogurt store sells servings up to 12 ounces. It charges $0.50 per ounce for a serving between 0 and 8 ounces

True [87]

Answer:

p(w) - - - - - - p = 0.5w ; for 0 < w ≤ 8

p(w) - - - - - - p = 4 ; for w < 8 and w ≤ 12

Step-by-step explanation:

Price, p of weight of a toughurt serving :

p(w) - - - - - - p = 0.5w ; for 0 < w ≤ 8

p(w) - - - - - - p = 4 ; for w < 8 and w ≤ 12

4 0

3 years ago