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3 years ago

Choose a number line to model the following situation:

Mathematics

2 answers:

katrin2010 [14]3 years ago

7 0

It is the first one because if u gain an amount and lose that same amount you don't gain anything.
25-25=0

babunello [35]3 years ago

5 0

Answer:

First number line.

Step-by-step explanation:

Given : After a gain of 25 yards, the football team lost 25 yards on the next play.

To find : Choose a number line to model the following situation:

Solution : We have given

gain of 25 yards, the football team lost 25 yards on the next play.

We use positive value for gain = + 25.

We use positive value for lost = - 25.

In the number line First we go to 0 to 25 to right and then come back 25 to 0 to left then , we will reach again at 0.

+25 - 25 = 0.

First number line represent the situation .

Therefore, First number line.

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You invested $ 7000 between two accounts paying 3 % and 5 % annual? interest, respectively. If the total interest earned for the

natita [175]

Answer:

In the first account was invested $\$3,000$ at 3%

In the second account was invested $\$4,000$ at 5%

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

First account

$t=1 years\\ P=\$x\\ r=0.03$

substitute in the formula above

$I=x(0.03*1)$

$I=0.03x$

Second account

$t=1 years\\ P=\$(7,000-x)\\ r=0.05$

substitute in the formula above

$I=(7,000-x)(0.05*1)$

$I=350-0.05x$

Remember that

The interest is equal to $\$290$

Adds the interest of both accounts

$0.03x+350-0.05x=\$290$

$0.05x-0.03x=350-290$

$0.02x=60$

$x=\$3,000$

therefore

In the first account was invested $\$3,000$ at 3%

In the second account was invested $\$7,000-\$3,000=\$4,000$ at 5%

7 0

2 years ago

Find all the second partial derivatives. v = e5xey

Helga [31]

I'm taking the liberty of editing your function <span>v = e5xey: It should be
</span>
<span>v = e^5x^ey, with " ^ " indicating exponentiation.
</span>
Did you mean e^(5x) or (e^5)x? I'll assume it's e^(5x).

The partial of v = e^(5x)e^y with respect to x is e^(5x)(5)*e^y, or 25x*e^y.

The partial of v = e^(5x)e^y with respect to y is e^(5x)e^y.

5 0

3 years ago

In the figure, AB is parallel to CD, XY is the perpendicular bisector of AB, and E is the midpoint of XY. Prove that △AEB ≅ △DEC

Makovka662 [10]

Answer:

From top to bottom:

A, J, E, B, I, C, D, G, F, H

See below for more clarification.

Step-by-step explanation:

We are given that AB is parallel to CD, XY is the perpendicular bisector of AB, and E is the midpoint of XY. And we want to prove that ΔAEB ≅ ΔDEC.

Statements:

1) XY is perpendicular to AB.

Definition of perpendicular bisector.

2) XY ⊥ CD.

In a plane, if a transveral is perpendicular to one of the two parallel lines, then it is perpendicular to the other.

3) m∠AXE = 90°, m∠DYE = 90°.

Definition of perpendicular lines.

4) ∠AXE ≅ ∠DYE.

Right angles are congruent.

5) XE ≅ YE

Definition of a midpoint.

6) ∠A ≅ ∠D.

Alternate Interior Angles Theorem

7) ΔAEX ≅ ΔDEY

AAS Triangle Congruence*

(*∠A ≅ ∠D, ∠AXE ≅ ∠DYE, and XE ≅ YE)

8) AE ≅ DE

Corresponding parts of congruent triangles are congruent (CPCTC).

9) ∠AEB ≅ ∠DEC

Vertical Angles Theorem

10) ΔAEB ≅ ΔDEC

ASA Triangle Congruence**

(**∠A ≅ ∠D, AE ≅ DE, and ∠AEB ≅ ∠DEC)

3 0

3 years ago

This question is 2x2 get it right if you don't you will lose

Tresset [83]

Answer: You mean "x" like times? If so 4 x)

Step-by-step explanation:

4 0

2 years ago

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At Hoffman’s Bike Rentals, it cost $44 dollars for 8 hours. How many hours of bike use does a customer get per dollar?

SashulF [63]

Answer:

$5.50 per hour

Step-by-step explanation:

44 divided by 8 equals 5.5

5 0

2 years ago

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