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Mashcka [7]
3 years ago
5

Refer to the data set below​ (body mass index of​ men) and determine whether the requirement of a normal distribution is satisfi

ed. Assume that this requirement is loose in the sense that the population distribution need not be exactly​ normal, but it must be a distribution that is basically symmetric with only one mode.
84 79 82 74 78

Is the requirement of a normal distribution​ satisfied?
Mathematics
1 answer:
AnnyKZ [126]3 years ago
4 0

Answer:

Yes . The requirement of a normal distribution​ are satisfied.

Step-by-step explanation

The points of the data in the normal quantile plot lie close to a straight line.

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Which expression is equivalent to 7/2h - 3 (5h - 1/2)
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7/2h-3/2step-by-step

explicacion: 7/2h-3=37/2h5h

1/2= 3/2Expression made:37/2h 3/2

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How to change .365 to a percent
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Multipl .365 by 100 and you get 36.5%
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If the output number y is -52 (y=5x-2) what is the input number? SHOW WORK
nordsb [41]

Answer:

the input number is -10

Step-by-step explanation:

output is always y

input is always x

so instead of y, put -52

-52=5x-2  add 2 to each side to ger 5x by itself

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x is the input so the input is -10

8 0
3 years ago
2. An expression is shown below.
velikii [3]
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5 0
3 years ago
Distance between parallel lines y=3x+10 and y=3x-20
Alecsey [184]

1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).


2. Use formula d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}} to find the distance from point (x_0,y_0) to the line Ax+By+C=0.


The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:

d=\dfrac{|3\cdot 0-10-20|}{\sqrt{3^2+(-1)^2}}=\dfrac{30}{\sqrt{10}}=3\sqrt{10}.


3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.


Answer: d=3\sqrt{10}.

4 0
3 years ago
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