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S_A_V [24]
3 years ago
14

Which expression is equivalent to the given expression after using the distributive property?

Mathematics
2 answers:
Nonamiya [84]3 years ago
8 0

Answer:

Step-by-step explanation:

4*(x + 5) + 8x = 4*x + 4*5 + 8x

                       = 4x + 20 + 8x

                        = 4x + 8x + 20

                       = 12x + 20

aniked [119]3 years ago
6 0

We've been given to find out the exactly same equivalent expression for the equation 4(x + 5) + 8x by using distributive property.

Distributive property is nothing but it is a simple property in mathematics which is very common to use and help to simply the equation.

Now, multiplying 4 to the (x + 5) we get,

\implies\sf{4(x + 5) + 8x}

\implies\sf{4x + 20 + 8x}

\implies\sf{4x + 8x + 20}

\implies\sf{12x + 20}

  • The simplest equivalent expression is 12x + 20
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Answer:

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Step-by-step explanation:

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If it takes 10 seconds for 10 printers to print out 10 pages of paper, how many seconds will it take 50 printers to print out 50
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Lets use the formula RWT=J to solve this, where,

  • R is the rate
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<em><u>"If it takes 10 seconds for 10 printers to print out 10 pages of paper"</u></em> - here -

W is 10 printers, T is 10 seconds,  and J is 10 pages. We can write:

R(10)(10)=10\\R(100)=10\\R=\frac{10}{100}\\R=0.1


<u><em>"how many seconds will it take 50 printers to print out 50 pages of paper"</em></u><em> - here we use R=0.1 (previously found) to figure out T.</em>

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George had 1 sheet of paper.He cuts it into 6 inches by 5 inches,and 3 inches by 6 inches.What were the dimension and total area
7nadin3 [17]

Answer:

A. 8 inches by 6 inches.

B. 48\text{ inches}^{2}.

Step-by-step explanation:

We have been given that George had 1 sheet of paper. He cuts it into 6 inches by 5 inches and 3 inches by 6 inches.

We can see that two dimensions of small parts of paper sheet have one dimension same (6 inches), therefore, one dimension of original sheet of paper will be 6 inches.

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Therefore. the area of original sheet of paper will be 48\text{ inches}^{2}.

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