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natulia [17]
2 years ago
6

How do you show 80 degrees in an angle

Mathematics
2 answers:
Karolina [17]2 years ago
5 0
Well a right angle is 90° so all u have to do is take 10° away from that
dusya [7]2 years ago
5 0
If 90 degrees is right angle, so just take 10 degrees away from that.
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Draw a model, solve problem 5 ×14
slega [8]

Answer:

70


Step-by-step explanation:


4 0
3 years ago
A snake is 2 ft 4" long how long is the snake?
Lesechka [4]
The snake is 2-ft 4-inches long.
I learned that from reading the question carefully,
including all of the given information..
5 0
2 years ago
Read 2 more answers
A transformation T: (x, y) (x + 3, y + 1). For the ordered pair (4, 3), enter its preimage point. (-1, 2) (1, 2) (7, 4)
Aleksandr-060686 [28]

Answer:

(1,2)

Step-by-step explanation:

we know that

The rule of the transformation is equal to

(x, y)  ------> (x + 3, y + 1)

Pre-image -----> Image

(x, y)  ------> (4, 3)

so

x+3=4 ----> x=4-3=1

y+1=3 ---> y=3-1=2

therefore

The pre-image is the point (1,2)

6 0
3 years ago
I’m having a hard time understanding substitution. Please help!
Vikentia [17]

b_1=\frac{2A}{h}-b_2

Step-by-step explanation:

Given expression is;

A=\frac{h(b_1+b_2)}{2}

Solving for b_1

Multiplying both sides by 2

2*A=\frac{h(b_1+b_2)}{2}*2\\2A=h(b_1+b_2)

Dividing both sides by h

\frac{2A}{h}=\frac{h(b_1+b_2)}{h}\\\frac{2A}{h}=b_1+b_2

Subtracting b_2 from both sides

\frac{2A}{h}-b_2=b_1+b_2-b_2\\\frac{2A}{h}-b_2=b_1\\b_1=\frac{2A}{h}-b_2

b_1=\frac{2A}{h}-b_2

Keywords: division, subtraction

Learn more about subtraction at:

  • brainly.com/question/11145277
  • brainly.com/question/11150876

#LearnwithBrainly

3 0
3 years ago
AACB ~AEFD<br> x = [?]<br> Enter your answer in decimal form.
tia_tia [17]

Answer:

<h2>11.4</h2>

Solution,

∆ ACB = ∆ EFD

finding the value of X,

\frac{x}{3.8}  =  \frac{15}{5}

Apply cross product property

x \times 5 = 15 \times 3.8

Calculate the product

5x = 57

Divide both sides by 5

\frac{5x}{5}  =  \frac{57}{5}

Calculate

x = 11.4

Hope this helps...

Good luck on your assignment...

4 0
2 years ago
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