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3 years ago

If the cross section shown is congruent to the base of the rectangular prism above, what is true about the cross

Mathematics

1 answer:

Vladimir [108]3 years ago

5 0

Answer:The answer is A.It is parallel to the basses.

Step-by-step explanation:

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Please Help Best answer gets brainliest first answer gets five stars

Brrunno [24]

Hi,

(1/4)^−2−(5^0)(2)(1^−1)

=16−(5^0)(2)(1^−1)

=16−(1)(2)(1^−1)

=16−2(1^−1)

=16−(2)(1)

=16−2

=14

Have a great day!

4 0

3 years ago

Read 2 more answers

A store is having a sale on chocolate chips and walnuts. For 3 pounds of chocolate chips and 5 pounds of walnuts, the total cost

umka21 [38]

c = cost per pound of chocolate chips

w = cost per pound of walnuts.

$\bf \stackrel{\textit{3 lbs of "c"}}{3c}+\stackrel{\textit{5 lbs of "w"}}{5w}~~=~~\stackrel{\textit{costs}}{15} \\\\\\ \stackrel{\textit{12 lbs of "c"}}{12c}+\stackrel{\textit{2 lbs of "w"}}{2w}~~=~~\stackrel{\textit{costs}}{33} \end{cases}\qquad \impliedby \textit{let's use elimination} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{llccccccl} 3c+5w=15&\times (-4)\implies &-12c&+&-20w&=&-60\\ 12c+2w=33&&12c&+&2w&=&33\\ \cline{3-7}\\ &&0&&-18w&=&-27 \end{array}$

$\bf -18w=-27\implies w=\cfrac{-27}{-18}\implies \blacktriangleright w=\cfrac{3}{2} \blacktriangleleft \\\\\\ \stackrel{\textit{substituting on the 1st equation}}{3c+5\left(\cfrac{3}{2} \right)=15}\implies 3c+\cfrac{15}{2}=15 \implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{2}}{2\left( 3c+\cfrac{15}{2} \right)=2(15)} \\\\\\ 6c+15=30\implies 6c=15\implies c=\cfrac{15}{6}\implies \blacktriangleright c=\cfrac{5}{2} \blacktriangleleft$

6 0

3 years ago

What variable do you eliminate?<br> 4x + 8y = 20<br> - 4x + 2y = -30

sveticcg [70]

Y :!2!298-76-6-7-8-&-8-7-6

4 0

2 years ago

Points G, E, and O are collinear on segment GO, and GE:EO = 3:4. G is located at (-5,-1), O is located at (9,6). What are the co

pishuonlain [190]

Answer:

E = (1, 2)

Step-by-step explanation:

You want ...

(E -G) : (O -E) = 3 : 4

4(E -G) = 3(O -E) . . . . . . . . "cross multiply"

4E -4G = 3O -3E . . . . . . . . eliminate parentheses

7E = 4G + 3O . . . . . . . . . . . add 3E+4G

E = (4G +3O)/7 . . . . . . . . . .divide by 7

E = (4(-5, -1) +3(9, 6))/7 = (-20+27, -4+18)/7 = (7, 14)/7 . . . . fill in G and O

E = (1, 2)

4 0

3 years ago

Is the following shape a right triangle? how do you know?

Vladimir79 [104]

I would go with c. It looks like point b is where the right triangle is

7 0

3 years ago

Read 2 more answers