Answer:
Here we have the function:
S(t) = 500 - 400*t^(-1)
Then the rate of change at the value t, will be:
S'(t) = dS(t)/dt
This differentiation will be:
S'(t) = -400/t^2
Then:
a) the rate of change at t = 1 is:
S'(1) = -400/1^2 = -400
The rate of change after one year is -400
b) t = 10
S'(10) = -400/10^2 = -400/100 = -4
The rate of change after 10 years is -4, it reduced as the years passed, as expected.
Answer:
Proportional
Step-by-step explanation:
2.5 week 3 days = 20 days and 12 hours
2.5•7=17.5 17.5 +3 = 20.5
5 week 3 days = 38 days
5•7=35 35+3= 38 days
Answer:
Initial value = 14.7
Rate of change = 0.445
Step-by-step explanation:
Given the linear function :
P(d) = 0.445d + 14.7
The linear equation above takes the general. Form of a slope - intercept equation :
y = mx + c
Where ; m = slope or gradient = rate of change in y per unit change in x
c = intercept , which is the intial value of y when x = 0
Thus using the above information ;
Initial value = intercept value = 14.7
The rate of change is the slope value = 0.445
