Answer:
2(x - 3)(3x + 2)
Step-by-step explanation:
Given
6x² - 14x - 12 ← factor out 2 from each term
= 2(3x² - 7x - 6) ← factor the quadratic
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 3 × - 6 = - 18 and sum = - 7
The factors are - 9 and + 2
Use these factors to split the x- term
3x² - 9x + 2x - 6 ( factor the first/second and third/fourth terms )
= 3x(x - 3) + 2(x - 3) ← factor out (x - 3) from each term
= (x - 3)(3x + 2)
Thus
3x² - 7x - 6 = (x - 3)(3x + 2) and
6x² - 14x - 12 = 2(x - 3)(3x + 2) ← in factored form
