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Alex73 [517]
3 years ago
14

I need to know what the sum of 347.89 + 23.52!!!

Mathematics
2 answers:
Airida [17]3 years ago
6 0

Answer:


371.41


~Courtney


vodomira [7]3 years ago
5 0

Answer:371.41


Step-by-step explanation:

this is because you just need to carry the number over to the next place if the sum of the digits( example 8+9=17) if it is greater than 10

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Which two complex numbers that could have been added together to make -11+3i
irina [24]

Answer:

Step-by-step explanation:

There are an infinite number of possible solutions.

here's a few

(1 - 4i) + (-12 + 4i)

(-5.5 + 2i) + (-5.5 + i)

(-24 - 27i) + (13 + 30i)

3 0
3 years ago
36% of what number is 18? SHOW YOUR WORK
Murljashka [212]
So 36% of x is 18
percent is parts out of 100
36%=36/100=0.36
'of' can be translated as muitiply
0.36 times x=18
divide both sdies by .36
x=50
the number is 50
8 0
3 years ago
Read 2 more answers
As a fraction in simplest terms, what would you multiply the first number by to get the second?
Alinara [238K]

Answer:

22/25

Step-by-step explanation:

66/75 = 22/25

Input into equation to confirm

75 · 22/25 = 66

1650/25 = 66

66 = 66, so we're right

5 0
2 years ago
Find the quotient of these Complex Numbers. <br><br><br> (5-i) / (3+2i)
JulsSmile [24]

Let the given complex number

z = x + ix = \dfrac{5-i}{3+2i}

We have to find the standard form of complex number.

Solution:

∴ x + iy = \dfrac{5-i}{3+2i}

Rationalising numerator part of complex number, we get

x + iy = \dfrac{5-i}{3+2i}\times \dfrac{3-2i}{3-2i}

⇒ x + iy = \dfrac{(5-i)(3-2i)}{3^2-(2i)^2}

Using the algebraic identity:

(a + b)(a - b) = a^{2} - b^{2}

⇒ x + iy = \dfrac{15-10i-3i+2i^2}{9-4i^2}

⇒ x + iy = \dfrac{15-13i+2(-1)}{9-4(-1)} [ ∵ i^{2} =-1]

⇒ x + iy = \dfrac{15-2-13i}{9+4}

⇒ x + iy = \dfrac{13-13i}{13}

⇒ x + iy = \dfrac{13(1-i)}{13}

⇒ x + iy = 1 - i

Thus, the given complex number in standard form as "1 - i".

5 0
3 years ago
Write me What is 10/12 using simplest form
Serjik [45]
Found it online hope that’s helps

8 0
3 years ago
Read 2 more answers
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