Let the speed for the first 12 mi be x mi/h, the speed for 18 mi was (x+4) mi/h
thus given that
time=distance/speed
the average time will be:
3=(12+18)/(x+x+4)
3=30/(2x+4)
solving for x we get
3(2x+4)=30
6x+6=30
6x=24
x=4 mi/hr
Answer: 12 mi/hr
I'm pretty sure 10/63 is simplified.
Answer:
9x-4y-87
Step-by-step explanation:
2x-4y+7x-87
9x-4y-87
Answer:
The answer to your question is the last option
Step-by-step explanation:
Quadratic equation
2 = - x + x² - 4
Order the equation from the highest power to the lowest power. Do not consider 2 because it is not consider in the options given.
x² - x - 4 = 0
Identify a, b and c
(1) x² -(1) x - 4 = 0
a = 1 b = -1 c = - 6
Substitution
