Given that,
Sample size= 83
Mean number= 39.04
Standard deviation= 11.51
We know the critical t-value for 95% confidence interval which is equal to 1.989.
We also know the formula for confidence interval,
CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))
So, we have
CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)
CI= (39.04 - 2.513,39.04 + 2.513)
CI= (36.527,41.553)
Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).
Answer:
an infinite number of solutions
Step-by-step explanation:
−3x −17 = −17 −3x
left side = right side TRUE because -3x-17 is the same as -17-3x
we can rearrange the the equation
−3x −17 +17 = −17 +17−3x, add 17 on both sides of the equations
-3x = -3x, divide both sides by (-3)
x = x
Since this equation is <u>always true ( for any number ) </u>we have <u>an infinite number of solutions</u> (since there are is an infinity of numbers.)
Step-by-step explanation:
Let's look at what we know. We know that...
P=2000
r=0.04 (Change 4% to a decimal)
t=7 (25 years minus 18 years equals 7)
n=1
Since we are compounding each year, we need to use this equation: 
Now just plug the numbers in: (Answer to #1:) 
This equals 2631.86
When we round, this equals to $2,632. (Answer to #2).
The first one is B because of the first attachment. The second one is A because of the second attachment. The third one is C because of the expression used to solve for sum of angles:
(n-2)180
(8-2)180
1080
Hope this helps!
