Jessica has two strings. The first string measures 80 centimeters, and the second string measures 64 centimeters. She wants to c
1 answer:
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A. Factor the numerator as a difference of squares:
c. As
, the contribution of the terms of degree less than 2 becomes negligible, which means we can write
e. Let's first rewrite the root terms with rational exponents:
![\displaystyle\lim_{x\to1}\frac{\sqrt[3]x-x}{\sqrt x-x}=\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bx%5Cto1%7D%5Cfrac%7B%5Csqrt%5B3%5Dx-x%7D%7B%5Csqrt%20x-x%7D%3D%5Clim_%7Bx%5Cto1%7D%5Cfrac%7Bx%5E%7B1%2F3%7D-x%7D%7Bx%5E%7B1%2F2%7D-x%7D)
Next we rationalize the numerator and denominator. We do so by recalling
In particular,
so we have
For
and 
, we can simplify the first term:
So our limit becomes
c. As
e. Let's first rewrite the root terms with rational exponents:
Next we rationalize the numerator and denominator. We do so by recalling
In particular,
so we have
For
So our limit becomes
Answer:
Ava needs to add 50ml of cleaner.
Step-by-step explanation:
Ratio of cleaner : water = 1:7
This means that the total ratio;(water+cleaner) = 1+7 = 8
Find fraction of each item out of the total ratio of 8;
Fraction of water =
Fraction of cleaner =
Knowing the fractions, find the quantity of cleaner in <em>ml </em>out of a total of 400-ml;
Cleaner = (1/8 )*400 = 50ml
Therefore, Ava needs to add 50ml of cleaner.