B.) Hibiscus Street
The key thing to remember is the slope of the lines. The equation for a line in slope intercept form is
y = ax + b
where
a = slope
b = y intercept
So the equation for Oak Street is y = 2/3x - 7. So it's slope is 2/3. And any street that has the same slope will be given a tree name. And any street that's perpendicular will be given a flower name. You can determine is a line is perpendicular if it has a slope that's the negative reciprocal. So a street that's perpendicular to Oak street will have a slope of -3/2.
Now you've just been given the equation to a new street that's y = -3/2x - 2. Since the slope is -3/2 and Oak street has a slope of 2/3, the new street is perpendicular to Oak street. And given the naming scheme, that means that the new street will have the name of a flower. So let's look at the available street names and pick a flower.
<span>
A.) Weeping Willow Street
* Nope a Weeping Willow is a tree. So this name won't work.
B.) Hibiscus Street
* Yes. A Hibiscus is a flower, so this name is suitable.
C.) Oak Street
* Nope. Not only is this a tree instead of a flower, but there's already an Oak street. So bad choice.
D.) Panther Street
* Nope, this is an animal, not a flower. Bad choice.
</span>
Answer:
Step-by-step explanation:
8) (5x + 23) + (17x - 41) = 180
22x = 198
x = 9
arc JK 5(9) + 23 = 68°
arc MJ 17(9) - 41 = 112°
arc LMK 360 - 112 = 248
9) 8x + (21x - 12) + (10x + 9) + 90 = 360
39x = 273
x = 7
arc WX 21(7) - 12 = 135°
arc YW 90 + 8(7) = 146°
arc YX 10(7) + 9 = 79°
arc VXW 360 - 8(7) = 304°
The discriminant is
which is 0.
Since the discriminant is 0, there is only one real solution.
Answer:
cos4B =1-8sin^2(B)+8sin^4(B)
Step-by-step explanation:
cos4B =1-8sin^2(B)+8sin^4(B)
