All categories

3 years ago

Estimate the total weight of two million pounds worth of two pence coins in kilograms. A two pence coin weighs 7.1g.

Mathematics

1 answer:

algol133 years ago

3 0

Answer: 710,000 kg

Step-by-step explanation:

There are 100 pence in one pound.

The number of two pence coins in 1 pound is therefore:

= 100 / 2

= 50 coins

In 2 million pounds therefore, there will be:

= 50 * 2,000,000

= 100,000,000 two pence coins

If one coin weighs 7.1g, weight is:

= 100,000,000 * 7.1

= 710,000,000 g

A kg is 1,000 grams so the weight in kg is:

= 710,000,000/1,000

= 710,000 kg

You might be interested in

Please help I will give Brainliest please!

WITCHER [35]

Part (a)

The domain is the set of allowed x inputs of a function.

The graph shows that x = 0 is not allowed because of the vertical asymptote located here. It seems like any other x value is fine though.

<h3>Domain: set of all real numbers but $x \ne 0$ </h3>

To write this in interval notation, we can say $(-\infty, 0) \cup (0, \infty)$ which is the result of poking a hole at 0 on the real number line.

--------------

The range deals with the y values. The graph makes it seem like it stretches on forever in both up and down directions. If this is the case, then the range is the set of all real numbers.

<h3>Range: Set of all real numbers</h3>

In interval notation, we would say $(-\infty, \infty)$ which is almost identical to the interval notation of the domain, except this time of course we aren't poking at hole at 0.

=======================================================

Part (b)

<h3>The x intercepts are x = -4 and x = 4</h3>

We can compact that to the notation $x = \pm 4$

These are the locations where the blue hyperbolic curve crosses the x axis.

=======================================================

Part (c)

<h3>Answer: There aren't any horizontal asymptotes in this graph.</h3>

Reason: The presence of an oblique asymptote cancels out any potential for a horizontal asymptote.

=======================================================

Part (d)

The vertical asymptote is located at x = 0, so the equation of the vertical asymptote is naturally x = 0. Every point on the vertical dashed line has an x coordinate of zero. The y coordinate can be anything you want.

<h3>Answer: x = 0 is the vertical asymptote</h3>

=======================================================

Part (e)

The oblique or slant asymptote is the diagonal dashed line.

It goes through (0,0) and (2,6)

The equation of the line through those points is y = 3x

If you were to zoom out on the graph (if possible), then you should notice the branches of the hyperbola stretch forever upward but they slowly should approach the "fencing" that is y = 3x. The same goes for the vertical asymptote as well of course.

<h3>Answer: Oblique asymptote is y = 3x</h3>

5 0

3 years ago

Jordan is cutting a 2 meter by 1 1/4 meter into two pieces by its diagonal line

Airida [17]

Question:

Jordan is cutting a 2 meter by $1\frac{1}{4}$ meter piece of rectangular paper into two pieces along its diagonal. what is the area of each of the pieces?

Answer:

Area of each piece of paper is $1 \frac{1}{4} \ m^2$ .

Solution:

Length of the paper = 2 m

Width of the paper = $1\frac{1}{4}$ m = $\frac{5}{4}$ m

<em>Area of the rectangle = length × width</em>

$$=2\times \frac{5}{4}$

$$= \frac{5}{2} \ m^2$

<em>Diagonal of a rectangle divides it into two equal parts.</em>

Area of each piece = Area of the rectangle ÷ 2

$$=\frac{ \frac{5}{2}}{2}$

$$=\frac{5}{4} \ m^2$

$$=1 \frac{1}{4} \ m^2$

Area of each piece of paper is $1 \frac{1}{4} \ m^2$ .

7 0

3 years ago

Write equation of a line perpendicular to the y-axis that passes through the point (-4,-8)

babymother [125]

Answer:

y = -8

Step-by-step explanation:

Since the line is perpendicular to the y-axis, it will be a horizontal line that runs through (-4,-8).

When a line is perpendicular to the y-axis, the x-coordinate doesn't matter because the line will be horizontal, meaning it will be the same y value regardless of the x value. In this case, the y value is −8 throughout the line.

Please mark as Brainliest ;)

5 0

2 years ago

Read 2 more answers

Suppose Mr. Kraus is 1.75m tall. When her shadow is 1m, how long would the shadow be of a 265m tall building?

BaLLatris [955]

Answer:

151.43 meters

Step-by-step explanation:

We can use ratios to solve

1.75m 265m

--------------- = -----------

1 m x meters

Using cross products

1.75x = 265*1

Divide each side by 1.75

1.75x/1.75 = 265/1.75

x =151.4285714

151.43 meters

6 0

3 years ago

Read 2 more answers

Using the distributive property answer this 11x + 9x

alina1380 [7]

You cant use the distributive property on this. but ill love to simplify this. the answer is 20x

6 0

3 years ago