Estimate the total weight of two million pounds worth of two pence coins in kilograms. A two pence coin weighs 7.1g.

Mathematics

1 answer:

algol133 years ago

3 0

Answer: 710,000 kg

Step-by-step explanation:

There are 100 pence in one pound.

The number of two pence coins in 1 pound is therefore:

= 100 / 2

= 50 coins

In 2 million pounds therefore, there will be:

= 50 * 2,000,000

= 100,000,000 two pence coins

If one coin weighs 7.1g, weight is:

= 100,000,000 * 7.1

= 710,000,000 g

A kg is 1,000 grams so the weight in kg is:

= 710,000,000/1,000

= 710,000 kg

You might be interested in

PLEASE SOMEONE HELP ME<br> ( There are np answer choices)

FinnZ [79.3K]

Answer:

whhhhhh

Step-by-step explanation:

it is number 2 because i took the test

3 0

3 years ago

Ask your teacher find the limit. use l'hospital's rule where appropriate. if there is a more elementary method, consider using i

liberstina [14]

Answer:

ln(5/3)

Step-by-step explanation:

The desired limit represents the logarithm of an indeterminate form, so L'Hopital's rule could be applied. However, the logarithm can be simplified to a form that is not indeterminate.

<h3>Limit</h3>

We can cancel factors of (x-1), which are what make the expression indeterminate at x=1. Then the limit can be evaluated directly by substituting x=1.

$\diplaystyle \lim\limits_{x\to1}{(\ln(x^5-1)-\ln(x^3-1))}=\lim\limits_{x\to1}\ln{\left(\dfrac{x^5-1}{x^3-1}\right)}\\\\=\lim\limits_{x\to1}\ln\left(\dfrac{x^4+x^3+x^2+x+1}{x^2+x+1}\right)=\ln{\dfrac{5}{3}}$