0.1515 - 15/99 pls help mee
1 answer:
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Answer:
Let the coordinate of focus be
As per the statement: The base of an auditorium is in the form of an eclipse 200 feet long and 100 feet wide.
⇒Length of Major axis=base of an auditorium = 200 feet and Length of a minor axis=wide of a auditorium = 100 ft
Semi-major axis (a) = 100 ft and
semi-minor axis(b) = 50 ft
Then, by an equation:
Solve for c:
Substitute the given values we have;
Simplify:
or
ft
Distance between the foci is,
Therefore, the distance between the foci to the nearest 10th of a foot is, 173.2 ft
