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babunello [35]
3 years ago
13

What is the 32nd term of the arithmetic sequence where a1 = -32 and a9 = -120? Choose one answer. A) -384. B) -373. C) -362. D)

-351
Mathematics
2 answers:
Alex3 years ago
5 0

Answer:

Step-by-step explanation:

Alright, lets get started.

The formula for nth term of arithmetic sequence is :

t_{n}=a+(n-1)d

First term is -32

Ninth term is :

t_{9}=-32 + (9-1)*d

-120=-32+8*d

8d=-120+32

8d=-88

d=-11

32th term is :

t_{32}=-32 + (32-1)*(-11)

t_{32}=-32-341

t_{32}=-373

So the answer is -373   :    Answer

Hope it will help :)

Inga [223]3 years ago
3 0
A 1 = - 32,  a 9 = - 120
a 9 = a 1 + 8 d
- 120 = - 32 + 8 d
8 d = - 88
d = - 88 : 8
d = - 11
a 32  = a 1 + 31 d = - 32 + 31 * ( -11 ) = - 32 - 341 = - 373
Answer: B ) - 373 

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