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love history [14]
3 years ago
9

Business ethics are?

Computers and Technology
1 answer:
bija089 [108]3 years ago
3 0
Business ethics are moral principles that guide the way a business behaves. The same principles that determine an individual”s actions also apply to business.
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IN EXCEL, File, menu , edit, insert are all located in ?
abruzzese [7]

Answer:

menu bar is the correct answer

hope it helps☺️

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2 years ago
I need help making a survey for highschool students in my school any topics/questions?
givi [52]

Answer:

depends is it just a survey? because if it doesent matter about the questions ou can do basic quuestions such as "what is your favorite video games" or "what is your favorite food"?

Explanation:

4 0
3 years ago
If you have questions about taxes, where can you go to get answers?
Andrews [41]

Answer:

Explanation:

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4 0
2 years ago
Finish and test the following two functions append and merge in the skeleton file:
avanturin [10]

Answer:

Explanation:

#include <iostream>

using namespace std;

int* append(int*,int,int*,int);

int* merge(int*,int,int*,int);

void print(int*,int);

int main()

{ int a[] = {11,33,55,77,99};

int b[] = {22,44,66,88};

print(a,5);

print(b,4);

int* c = append(a,5,b,4); // c points to the appended array=

print(c,9);

int* d = merge(a,5,b,4);

print(d,9);

}

void print(int* a, int n)

{ cout << "{" << a[0];

for (int i=1; i<n; i++)

cout << "," << a[i];

cout << "}\n";

}

int* append(int* a, int m, int* b, int n)

{

int * p= (int *)malloc(sizeof(int)*(m+n));

int i,index=0;

for(i=0;i<m;i++)

p[index++]=a[i];

for(i=0;i<n;i++)

p[index++]=b[i];

return p;

}

int* merge(int* a, int m, int* b, int n)

{

int i, j, k;

j = k = 0;

int *mergeRes = (int *)malloc(sizeof(int)*(m+n));

for (i = 0; i < m + n;) {

if (j < m && k < n) {

if (a[j] < b[k]) {

mergeRes[i] = a[j];

j++;

}

else {

mergeRes[i] = b[k];

k++;

}

i++;

}

// copying remaining elements from the b

else if (j == m) {

for (; i < m + n;) {

mergeRes[i] = b[k];

k++;

i++;

}

}

// copying remaining elements from the a

else {

for (; i < m + n;) {

mergeRes[i] = a[j];

j++;

i++;

}

}

}

return mergeRes;

}

4 0
3 years ago
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