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Rzqust [24]
3 years ago
13

Ubehebe crater in Death Valley has a diameter of a little more than 1/2 mile. If latisha walks around it's rim at a rate of 2 mi

les per hour, about how long will it take her to walk all the way around the crater? Find your answer to the nearest tenth. Use 3.14 for pie
Mathematics
2 answers:
Yuri [45]3 years ago
8 0
Let's say that the diameter was 1/2 mile. So the diameter is 1/2,  then you need to find the circumference, aka perimeter of the circle. So 1/2 times 3.14 = 1.57 miles So then you would do 1.57/2 = .785 of an hour If you round to nearest tenth The answer is .8 of an hour.
Triss [41]3 years ago
4 0

Answer:

It took Latisha <u>0.8 hour</u> to walk all the way around the crater

Step-by-step explanation:

Firstly, we write the parameters which we were given in the question

diameter (d) = 1/2 or 0.5 mile, velocity (v) = 2 miles per hour, π = 3.14

circumference of a circle (C) = 2πr

But 2 x radius ⇒ diameter, hence,

circumference of a circle = πd ⇒ 3.14 x 0.5 = 1.57 miles

C = <u>1.57 miles</u>

Therefore, the circumference of the crater is <u>1.57 miles</u>

To calculate how long it will take her to walk all the way around the crater, divide the distance (circumference of the crater) by speed (velocity). Mathematically represented as:

t = C ÷ v

t = 1.57 ÷ 2 = 0.785 hour

t = <u>0.8 hour</u> (to the nearest tenth)

It took Latisha 0.8 hour (or 48 minutes) to walk all the way around the crater

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sergij07 [2.7K]

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Answer:

  47 -6√10

Step-by-step explanation:

As you know, the area of a square is the square of the side length. It can be helpful here to make use of the form for the square of a binomial.

  (a -b)² = a² - 2ab + b²

  (√2 -3√5)² = (√2)² - 2(√2)(3√5) + (3√5)²

  = 2 - 6√10 + 3²(5)

  = 47 -6√10

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<em>Check</em>

  √2-3√5 ≈ -5.29399 . . . . . . . . note that a negative value for side length makes no sense, so this isn't about geometry, it's about binomials and radicals

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3 years ago
What is the area of the semicircle?
mihalych1998 [28]
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3 years ago
What is the gcf of 3/7 and 4/9?
LiRa [457]

Answer:

  1/63

Step-by-step explanation:

There are a couple of ways to do this.

<h3>1) </h3>

Look for the GCF of the numerators when a common denominator is used.

  GCF(3/7, 4/9) = GCF(27/63, 28/63) = (1/63)·GCF(27, 28)

  GCF(3/7, 4/9) = 1/63

__

<h3>2) </h3>

Use Euclid's algorithm. If the remainder from division of the larger by the smaller is zero, then the smaller is the GCF; otherwise, the remainder replaces the larger, and the algorithm repeats.

  (4/9)/(3/7) = 1 remainder 1/63*

  (3/7)/(1/63) = 27 remainder 0

The GCF is 1/63.

__

* The quotient is 28/27 = 1 +1/27 = 1 +(1/27)(3/7)/(3/7) = 1 +(1/63)/(3/7) or 1 with a remainder of 1/63.

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<em>Additional comment</em>

3/7 = (1/63) × 27

4/9 = (1/63) × 28

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Answer:

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Step-by-step explanation:

To find the midpoint, the formula is (x1-x2)/2 and (y1-y2)/2. So, in this case, our x1 is 4 1/2 and our x2 is -3 1/4. Subtract x2 from x1 and you will get 7 3/4. Then, divide by 2 to get 3 7/8. This is our x-coordinate.

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Now we have our x and y coordinates.

(3 7/8, 2 3/4)

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