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BigorU [14]
3 years ago
10

Translate to an algebraic expression 35 less than y. 40 POINTS EASY!!!!!!!!!

Mathematics
1 answer:
alina1380 [7]3 years ago
7 0

Answer:

Step-by-step explanation:

y - 35

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BRAINLIEST TO CORRECT QUICKLY
Pani-rosa [81]

Answer:

-6 3/8 < -7/8

Step-by-step explanation:

Answer:

-6 3/8 < -7/8

Showing Work

Using the given inputs:

-6 3/8 -7/8

Rewriting these inputs as improper fractions:

-51/8 and -7/8

Since we have like denominators we compare the inputs by the numerators:

Therefore, comparison shows:

-6 3/8 < -7/8

8 0
2 years ago
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Same this for me but 6,912 and 288 please help
Svetllana [295]

Answer:

what is the question

Step-by-step explanation:

Questions for answers

4 0
3 years ago
Remove the parentheses and simplify 3a^2-6ab+3b^2-5(-6a^2+7ab-7b^2) 
Oksi-84 [34.3K]
3a^2-6ab+3b^2-5(-6a^2+7ab-7b^2)=\\\\3a^2-6ab+3b^2+30a^2-35ab+35b^2=\\\\33a^2-41ab+38b^2
4 0
3 years ago
The Difference of 4 and k, divided by 16.
miskamm [114]

Answer:4-k÷6

Step-by-step explanation:

5 0
2 years ago
Liquid A has a density of 0.7g/cm^3
TiliK225 [7]
\rho = \frac{m}{V} \Rightarrow V=\frac{m}{\rho}
ρ - density, m - mass, V - volume

Liquid A:
\rho=0.7 \ \frac{g}{cm^3} \\&#10;m=140 \ g \\&#10;\\ V=\frac{140 \ g}{0.7 \ \frac{g}{cm^3}}=200 \ cm^3

Liquid B:
\rho=1.6 \ \frac{g}{cm^3} \\&#10;m=128 \ g \\&#10;\\ V=\frac{128 \ g}{1.6 \ \frac{g}{cm^3}}=80 \ cm^3

Liquid C:
m=140 \ g + 128 \ g=268 \ g \\&#10;V=200 \ cm^3 + 80 \ cm^3=280 \ cm^3 \\ \\&#10;\rho=\frac{268 \ g}{280 \ cm^3} \approx 0.96 \ \frac{g}{cm^3}

The density of liquid C is approximately 0.96 g/cm³.
5 0
3 years ago
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