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igomit [66]
3 years ago
10

What is an equation of the line that passes through (-2,3) and is parallel to y=5x + 4.Give your answer in slope intercept form

[y=mx+b]
Mathematics
1 answer:
9966 [12]3 years ago
8 0

Answer:

y= 5x+13

Step-by-step explanation:

<u>Slope- intercept form</u>

y= mx +b, where m is the gradient and b is the y-intercept.

Parallel lines have the same gradient.

y= 5x +4

Gradient of given line= 5

Thus, gradient of line= 5

Subst. m=5 into the equation.

y= 5x +b

To find the value of b, substitute a coordinate

When x= -2, y=3,

3= 5(-2) +b

3= -10 +b

b= 3 +10 <em>(</em><em>+</em><em>1</em><em>0</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

b= 13

Thus, the equation of the line is y= 5x +13.

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Find the length of the following curve. If you have a​ grapher, you may want to graph the curve to see what it looks like.
stepladder [879]

The length of the curve y = \frac{1}{27}(9x^2 + 6)^\frac 32 from x = 3 to x = 6 is 192 units

<h3>How to determine the length of the curve?</h3>

The curve is given as:

y = \frac{1}{27}(9x^2 + 6)^\frac 32 from x = 3 to x = 6

Start by differentiating the curve function

y' = \frac 32 * \frac{1}{27}(9x^2 + 6)^\frac 12 * 18x

Evaluate

y' = x(9x^2 + 6)^\frac 12

The length of the curve is calculated using:

L =\int\limits^a_b {\sqrt{1 + y'^2}} \, dx

This gives

L =\int\limits^6_3 {\sqrt{1 + [x(9x^2 + 6)^\frac 12]^2}\ dx

Expand

L =\int\limits^6_3 {\sqrt{1 + x^2(9x^2 + 6)}\ dx

This gives

L =\int\limits^6_3 {\sqrt{9x^4 + 6x^2 + 1}\ dx

Express as a perfect square

L =\int\limits^6_3 {\sqrt{(3x^2 + 1)^2}\ dx

Evaluate the exponent

L =\int\limits^6_3 {3x^2 + 1} \ dx

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L = x^3 + x|\limits^6_3

Expand

L = (6³ + 6) - (3³ + 3)

Evaluate

L = 192

Hence, the length of the curve is 192 units

Read more about curve lengths at:

brainly.com/question/14015568

#SPJ1

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1 year ago
Find the simple interest paid on a loan of $750 with an 18% rate over 2 years.
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Answer: $270

Step-by-step explanation:

I = prt

I = 0.18 x 750 x 2

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I = 270

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