Answer:
3.36 cm
Step-by-step explanation:
from the passage before ; the figure of question is similar to the first figure in passage because those triangles have an each equal angle.
Therefore the ratio of side is equal ; 1/0.84=4/x
Solve equation will be x(1)=4(0.84) ; x=3.36 cm
The way you should go about solving this really depends on how your teacher taught you...However, here's what I would recommend...
You know that 1/2 an hour is equal to 30 minutes, and 3/4 of an hour is equal to 45 minutes.
Using this you can then solve for how many pages she read per minute by dividing the number of pages read by the number of minutes read:11 pages/ 30 minutes to give you Monday's reading speed,and18 pages/ 45 minutes to give you Tuesday's reading speed.
Next, to calculate a percentage increase you need to do the following:
1. Determine the difference between the speeds (this means you will subtract Monday's reading speed from Tuesday's reading speed.)
2. Next you take that number and divide it by Monday's reading speed.
3. Multiply that answer by 100 to get the percentage.
I'm not going to tell you the speeds, as you should try to attempt to solve it by yourself, and I'm sure you need to show your work. I will however tell you that you should find there was a 3.3% increase from Monday to Tuesday.
If you need more help, let me know!
The correct answer: total interest = $1,784.56 and she would have $4,284.56 after 7 years
That is a ratio. If you mean the simplified version, then 2:7
Functions: the chart with number values, the dot graph, and the middle graph on the right
Not functions: the top graph on the left with the vertical line, the graph with the circle, and the bottom right graph
Any graph that doesn’t pass the vertical line test is not a function. You can do this by starting at the top of the graph and drawing a line straight down through what you are testing. If you pass through the line or circle more than once it is not a function.
If you look at the number values if the x value repeats more than once it is not a function.
