Answer:
3x +15y +7z = 46
Step-by-step explanation:
The cross product of v = <2, 1, -3> and PQ = <-5, 1, 0> is <3, 15, 7>, the normal vector of the plane of interest. That plane contains P and Q, so the constant in the plane's equation will be ...
<3, 15, 7> · <3, 2, 1> = 46
The desired equation is ...
3x +15y +7z = 46
Answer:
Step-by-step explanation:
Given the coordinate points (6, -3) and (7, -10), we are to find the equation of a line passing through this two points;
The standard equation of a line is y = mx+c
m is the slope
c is the intercept
Get the slope;
m = Δy/Δx = y2-y1/x2-x1
m = -10-(-3)/7-6
m = -10+3/1
m = -7
Get the intercept;
Substitute the point (6, -3) and m = -7 into the expression y = mx+c
-3 = -7(6)+c
-3 = -42 + c
c = -3 + 42
c = 39
Get the required equation by substituting m = -7 and c= 39 into the equation y = mx+c
y = -7x + 39
Hence the required equation is y = -7x + 39
Answer=3610.201
3*1000=3,000
6*100=600
1*10=10
2*1/10=0.2
1*1/1000=0.001
3000+600+10+0.2+0.001=3610.201
