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tamaranim1 [39]
3 years ago
6

Rewrite the radical as a rational exponent. the cube root of 2 to the seventh power

Mathematics
1 answer:
storchak [24]3 years ago
7 0
\bf a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-------------------------------\\\\
\sqrt[3]{2^7}\implies 2^{\frac{7}{3}}
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4 years ago
Describe the relationship between n and 4 that will make the value of the expression 6 x n/4 greater than 6.
KatRina [158]

Answer:

n is greater than 4

Step-by-step explanation:

We have to find the relation between n and 4 for which (6\times \frac{n}{4}) is greater 6.

Converting this verbal expression into algebraic expression,

(6\times \frac{n}{4})>6

(6\times \frac{n}{6\times 4})>\frac{6}{6}

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n > 4

Therefore, relation between n and 4 is "n is greater than 4".

8 0
3 years ago
Identify the properties used in Step 1 and Step 2 to solve the equation shown. Then discuss why those properties were used. Prob
Alex Ar [27]
<h3>Step-by-step explanation:</h3>

<u>Step</u>                <u>Property</u>

2x+6 = 22       given

2x = 16            addition property of equality (-6 added to both sides)

x = 8                multiplication property of equality (both sides × 1/2)

_____

In general equations are solved by reversing the steps done to the variable. Here, the variable (x) is multiplied by 2 and 6 is added to that product. So, to find x, we undo the addition of 6 (by adding -6, the additive inverse), and undo the multiplication by 2 (by multiplying by 1/2, the multiplicative inverse).

If other functions were performed on the variable in the original equation, their inverse functions would be used, too, as part of the solution process.

7 0
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How to do this equation y=2x-10 and 2y=x-8
Lana71 [14]

Answer:

y=2x-10

2y=x-8

since the second equation equals 2y and the first is y that means the first equation times 2 equals the other one

4x-20=x-8

-x

3x-20=-8

+20

3x=12

x=4

then lets just plug it in

2y=4-8

simplefy

2y=-4

y=-2

(4,-2)

Hope This Helps!!!

8 0
2 years ago
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