Area and distributive property 14-5

3360832553 ____ pass___ wZE2XQ

Anvisha [2.4K]

Answer:

what? i really dont understand

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The prior probabilities for events A1 and A2 are P(A1) = 0.20 and P(A2) = 0.80. It is also known that P(A1 ∩ A2) = 0. Suppose P(

Umnica [9.8K]

Answer:

(a) $A_1$ and $A_2$ are indeed mutually-exclusive.

(b) $\displaystyle P(A_1\; \cap \; B) = \frac{1}{20}$ , whereas $\displaystyle P(A_2\; \cap \; B) = \frac{1}{25}$ .

(c) $\displaystyle P(B) = \frac{9}{100}$ .

(d) $\displaystyle P(A_1 \; |\; B) \approx \frac{5}{9}$ , whereas $P(A_1 \; |\; B) = \displaystyle \frac{4}{9}$

Step-by-step explanation:

$P(A_1 \; \cap \; A_2) = 0$ means that it is impossible for events $A_1$ and $A_2$ to happen at the same time. Therefore, event $A_1$ and $A_2$ are mutually-exclusive.

By the definition of conditional probability:

$\displaystyle P(B \; | \; A_1) = \frac{P(B \; \cap \; A_1)}{P(B)} = \frac{P(A_1 \; \cap \; B)}{P(B)}$ .

Rearrange to obtain:

$\displaystyle P(A_1 \; \cap \; B) = P(B \; |\; A_1) \cdot P(A_1) = 0.25 \times 0.20 = \frac{1}{20}$ .

Similarly:

$\displaystyle P(A_2 \; \cap \; B) = P(B \; |\; A_2) \cdot P(A_2) = 0.80 \times 0.05 = \frac{1}{25}$ .

Note that:

$\begin{aligned}P(A_1 \; \cup \; A_2) &= P(A_1) + P(A_2) - P(A_1 \; \cap \; A_2) = 0.20 + 0.80 = 1\end{aligned}$ .

In other words, $A_1$ and $A_2$ are collectively-exhaustive. Since $A_1$ and $A_2$ are collectively-exhaustive and mutually-exclusive at the same time:

$\displaystyle P(B) = P(B \; \cap \; A_1) + P(B \; \cap \; A_2) = \frac{1}{20} + \frac{1}{25} = \frac{9}{100}$ .

By Bayes' Theorem:

$\begin{aligned} P(A_1 \; |\; B) &= \frac{P(B \; | \; A_1) \cdot P(A_1)}{P(B)} \\ &= \frac{0.25 \times 0.20}{9/100} = \frac{0.05 \times 100}{9} = \frac{5}{9}\end{aligned}$ .

Similarly:

$\begin{aligned} P(A_2 \; |\; B) &= \frac{P(B \; | \; A_2) \cdot P(A_2)}{P(B)} \\ &= \frac{0.05 \times 0.80}{9/100} = \frac{0.04 \times 100}{9} = \frac{4}{9}\end{aligned}$ .

6 0

3 years ago

Which common denominator can be used to add each pair of fractions? Match each pair of fractions to the common denominator that

Charra [1.4K]

Answer + Explanation

You look at the two denominators of the fractions and find the least common multiple of both of them.

1. the LCM of 2 and 5 is 10

2. the LCM of 3 and 5 is 15

3. the LCM of 4 and 6 is 12

4. the LCM of 6 and 9 is 18

6 0

3 years ago

Read 2 more answers

BRAINIEST TO WHIVER RIGHT HELP

Alex Ar [27]

The least value is the smallest number in a set. So in this case it would be 3 since the first marker marks 3 on the box plot.

5 0

3 years ago

Question 6 of 10

Verizon [17]

Answer:

Step-by-step explanation:

We have to tell about the statement true or false

Two triangles that have the same side length will always be congruent

The SSS congruency rule states that if all three sides of one triangle are equal to corresponding three sides of another triangle, then the triangles are congruent.

∴ we say that when the sides are the same then the triangles are congruent.

<u><em>Hence, the statement is true.</em></u>

Because the definition of a congruent triangle is a triangle with every side of same length.

6 0

3 years ago