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Pavel [41]
3 years ago
13

BRAINIEST TO WHIVER RIGHT HELP

Mathematics
1 answer:
Alex Ar [27]3 years ago
5 0
The least value is the smallest number in a set. So in this case it would be 3 since the first marker marks 3 on the box plot.
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I never really understood what this was could u help
ycow [4]

Answer:

1. f(4) or f(n)= 28

2. f(-2) or f(n)= -2

(please consider marking brainliest <3 )

Step-by-step explanation:

n=4                           n=-2

f(n)= 5(n)+8              f(n)= 5(n)+8

f(n)= 5(4)+8              f(n)= 5(-2)+8

(n)= 20+8                 f(n)= -10+8

f(n)=28                      f(n)=-2

5 0
3 years ago
Read 2 more answers
Ten more than 6 times a number is 4 less than 4 times the number. Please help me!!
Y_Kistochka [10]
10+6x=4x-4
6x-4x=-4-10
     2x=-14
      x-7
10=6(-7)=-32
4(-7)-4=-32
         =-32
6 0
4 years ago
One zero of x^3 - 4x = 0 is 0 what are the other zeros of the function
myrzilka [38]
So you have x^3 - 4x = 0. What you can do is pull out an x from both x^3 and - 4x so it looks like this:

x( {x}^{2} - 4) = 0

Then you can find a number that makes the part inside the parentheses turn into zero. For beginners, it may be easier to write it out seperately and solve for x.

{x}^{2} - 4 = 0

We need to solve for x, so the first step is to add 4 to both sides, so we get something like this:

{x}^{2} = 4

Then, we can square root both sides to get rid of the power on the x, so it looks like this:

x = \sqrt{4}

Now, every square root has two answers, a positive and a negative. If we look at the bottom example:

{2}^{2} = 4

{( - 2)}^{2} = 4

We can see that both -2 and 2 to the power of two will equal to 4.

So finally, we get:

x = - 2 \: and \: 2

These are the other 'Zero's for the original function. If you are not sure of what a 'Zero' is, it is where the function crosses over the x-axis on a graph.
5 0
3 years ago
HELP PLEASE ASAP MATH!!!!!
ArbitrLikvidat [17]
First answer is correct because angles DAB and EAD equal 180 degrees (supplementary)
6 0
3 years ago
NEED HELP PLEASE!!!!
Masja [62]

Answer:

Yes

Step-by-step explanation:

\sqrt{\frac{2x}{9} }={\frac{\sqrt{2x} }\sqrt{} {9} }  =\frac{\sqrt{2x} }{3}=\frac{1}{3}\sqrt{2x}

3 0
3 years ago
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