Answer:
E. 5
Step-by-step explanation:
Let's rewrite the equation in the form of y=mx+b, where m is the slope and b is the y-intercept (the value of y when x = 0).
2x + y = 5
y = -2x+5
M, the slope, is -2
<u>5, b, is the y-intercept</u>
See attached graph.
When roots of polynomials occur in radical form, they occur as two conjugates.
That is,
The conjugate of (a + √b) is (a - √b) and vice versa.
To show that the given conjugates come from a polynomial, we should create the polynomial from the given factors.
The first factor is x - (a + √b).
The second factor is x - (a - √b).
The polynomial is
f(x) = [x - (a + √b)]*[x - (a - √b)]
= x² - x(a - √b) - x(a + √b) + (a + √b)(a - √b)
= x² - 2ax + x√b - x√b + a² - b
= x² - 2ax + a² - b
This is a quadratic polynomial, as expected.
If you solve the quadratic equation x² - 2ax + a² - b = 0 with the quadratic formula, it should yield the pair of conjugate radical roots.
x = (1/2) [ 2a +/- √(4a² - 4(a² - b)]
= a +/- (1/2)*√(4b)
= a +/- √b
x = a + √b, or x = a - √b, as expected.
5x-1=19
1st you add the one over to the 19 and you'll get 20
then you do 5x=20
divide the 5x over to the 20 and your final answer is 4.
