Given:
Point D is incenter of ΔBCA.
m∠FDG = 136°
To find:
The measure of ∠FHG
Solution:
<em>Angle subtended by the arc at the center is twice that subtended on the remain part of the circle.</em>
Divided by 2 on both sides.
Substitute m∠FDG = 136°
The measure of ∠FHG is 68°.
