Answer:
The probability that 75% or more of the women in the sample have been on a diet is 0.037.
Step-by-step explanation:
Let <em>X</em> = number of college women on a diet.
The probability of a woman being on diet is, P (X) = <em>p</em> = 0.70.
The sample of women selected is, <em>n</em> = 267.
The random variable thus follows a Binomial distribution with parameters <em>n</em> = 267 and <em>p</em> = 0.70.
As the sample size is large (n > 30), according to the Central limit theorem the sampling distribution of sample proportions (
) follows a Normal distribution.
The mean of this distribution is:

The standard deviation of this distribution is: 
Compute the probability that 75% or more of the women in the sample have been on a diet as follows:

**Use the <em>z</em>-table for the probability.

Thus, the probability that 75% or more of the women in the sample have been on a diet is 0.037.
Answer:
1/6 ; 2/6 ; 2/6
Step-by-step explanation:
To split 5/6 into. 3 different fractions with the same denominator and different numerator values;
The integer value of the numerator 5 can be divided into 3 different whole Number values ;
It could be :
5 = 3 + 1 + 1
5 = 2 + 2 + 1
Hence, we could have ;
3/6 +. 1/6 + 1/6
Or
2/6 + 2/6 + 1/3
Answer: D
3x^2 - 6x + 20 - 62/x + 3
Hope this helps! :)
Square foot is a unit of area. find the area of the manhole. A = (pi)r^2
9.2 lbs per square foot multiplied by area in units of square feet gives lbs.
diameter is twice radius, so radius is 1.5 ft.
Area of manhole = (pi)(1.5)^2
lbs manhole = (9.2)(pi)(1.5)^2
= 65 lbs