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Natasha2012 [34]
3 years ago
9

The revenue R you receive for selling pizza slices depends on the price p that you charge per slice and is modeled by R =-16p

Mathematics
1 answer:
sp2606 [1]3 years ago
8 0

Answer:

p \geq 0

Step-by-step explanation:

Given

R(p) = -16p^2 + 80p + 5

Required

Determine the domain of the function

To do this, we need to solve for the vertex, p of the function

p= \frac{-b}{2a}

Given the the general form of a quadratic function is:

y = ax^2 + bx + c

By comparison, we have:

a = -16    b =80    c = 5

So:

p= \frac{-b}{2a}

p = \frac{-80}{-16 * 5}

p = \frac{-80}{-80}

p = 1

Substitute 1 for p in R(p) = -16p^2 + 80p + 5

R(1) = -16(1)^2 + 80(1) + 5

R(1) = -16 + 80 + 5

R(1) = 69

This implies that

(p, R) = (1,69)

The interpretation of this is that;

<em>For every value of p, there's a corresponding value of R.</em>

<em>However, because p indicates price and it's impossible to have a negative price, we can say that the minimum value of p is 0;</em>

Hence, the domain is

p \geq 0

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Answer:

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Step-by-step explanation:

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Function f is differentiable and decreasing for all real numbers. If y=f(2x^3 - 3x^2), for which of the following intervals of x
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Answer:

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Step-by-step explanation:

y′′ + 4y′ − 21y = 0

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m² + 4m - 21 = 0

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Also,

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Since y(1) = 1 and y'(1) = 0, we substitute them into the equations above. So,

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y'(1) = 3Ae^{3X1} - 7Be^{-7X1}\\0 = 3Ae^{3} - 7Be^{-7}\\3Ae^{3} - 7Be^{-7} = 0 \\3Ae^{3} = 7Be^{-7}\\A = \frac{7}{3} Be^{-10}

Substituting A into (1) above, we have

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Substituting B into A, we have

A = \frac{7}{3} \frac{3}{10} e^{7}e^{-10}\\A = \frac{7}{10} e^{-3}

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So the solution to the differential equation is

y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}

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