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3 years ago

Y=-1/4x+4 written in stander form

Mathematics

1 answer:

krok68 [10]3 years ago

5 0

Answer:

$\frac{1}{4}x+y=4$

Step-by-step explanation:

standard form is Ax + By = C
In short, get all the variables on the left and the constants on the right

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Simplify the following expression:

Morgarella [4.7K]

Answer:

2nd option

Step-by-step explanation:

Given

2x - 8y + 3x² + 7y - 12x ← collect like terms

= 3x² + (2x - 12x) + (- 8y + 7y)

= 3x² + (- 10x) + (- y)

= 3x² - 10x - y

8 0

3 years ago

X=0 100 200 300 y= 3.5 18.5 33.5 48.5

Elena L [17]

Answer:

try one try one try one try one

3 0

3 years ago

Over [174]

Answer:

2x + (x + 2)

Step-by-step explanation:

Let the number = x

"twice a number" means 2x

"increased by the sum of the same number and five" means to add x + 5, so the expression is

2x + (x + 2)

8 0

3 years ago

Please help me out with this :) and explain if you can

KonstantinChe [14]

Answer:

there are twelve total combinations

Step-by-step explanation:

just by looking at the problem though,

ABCD

normally, because some of them are repeated, we need to get rid of some

since this is about passwords though, we need to keep all of the same twelve combinations because the order of the letters are important

6 0

3 years ago

How many nanoseconds does it take for a computer to perform one calculation if it performs 6.7 × 10^{7} calculations per second?

crimeas [40]

Answer:

the comuter does 1 calculation in 1.5* $10^{-17}$ nanosec

Step-by-step explanation:

First step: we need to write all terms in nanosec, as we know:

1[nanosec]= $10^{-9}$ [sec]

The computer does 6.7* $10^{7}$ [ $\frac{calculation}{sec}$ ]

if we multiplicate for $\frac{sec}{nanosec*10^{*9}}$ , from the units convertion.

6.7* $10^{7}$ [ $\frac{calculation}{sec}$ * $\frac{sec}{nanosec*10^{*9}}$

6.7* $10^{16}$ [ $\frac{calculation}{nanosec}$ ]

Now doing a simple three rule we have this:

6.7 * $10^{16}$ calculation in ⇒ 1 nanosec

1 calculation in ⇒ $\frac{1 nanosec* 1calculation}{6.7*10^{16} calculation }$

So, we found: the comuter does 1 calculation in 1.5* $10^{-17}$ nanosec

8 0

3 years ago