Answer:
Use the quadratic formula
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.
5
2
−
4
1
+
8
=
0
5x^{2}-41x+8=0
5x2−41x+8=0
=
5
a={\color{#c92786}{5}}
a=5
=
−
4
1
b={\color{#e8710a}{-41}}
b=−41
=
8
c={\color{#129eaf}{8}}
c=8
=
−
(
−
4
1
)
±
(
−
4
1
)
2
−
4
⋅
5
⋅
8
√
2
⋅
5
2
Simplify
3
Separate the equations
4
Solve
Solution
=
8
=
1
5
Answer:
160 not interested and 144*
Step-by-step explanation:
* is the degree sign like the little o
Answer:
16*j+4
16+8*4
16+32
48
Step-by-step explanation:
Answer:
To find the volume of a cube one must multiply all three dimensions together. Here we know two of the dimensions and the volume but not the third dimension. First I multipl together to two known dimensions: 3/4 x 1/2 = 3/8. Next I divide the volume by this answer by using the reciprocal of 3/8 and multipling. 21/32 x 8/3 = 7/4 by cancelling the 32 with the 8 and the 21 with the 3. Now 7/4 must be changed into a mixed number. Divide the numerator by the denominator and write the remainder as a fraction. 7/4 = 1 3/4.
Answer:
sin θ = 15/17
Step-by-step explanation:
First we have to know how much the hypotenuse measures.
to take out the hypotenuse we will use pitagoras, with the following formula.
h^2 = c1^2 + c2^2
c1 = 8
c2 = 15
h^2 = 8^2 + 15^2
h^2 = 64 + 225
h = √ 289
h = 17
well to start we have to know the relationships between angles, legs and the hypotenuse.
a: adjacent
o: opposite
h: hypotenuse
sin θ = o/h
cos θ= a/h
tan θ = o/a
we want to know the sin of θ
sin θ = o/h
sin θ = 15/17
