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GaryK [48]
3 years ago
7

Y=-1/4x+4 written in stander form

Mathematics
1 answer:
krok68 [10]3 years ago
5 0

Answer:

\frac{1}{4}x+y=4

Step-by-step explanation:

  • standard form is Ax + By = C
  • In short, get all the variables on the left and the constants on the right
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I’m not sure how to go about this could you please help me in how to solve it?
REY [17]
Hmm not sure how to do this but I am sure other people will help you thank you so much
8 0
3 years ago
If VX = WZ = 40 cm and m∠ZVX = m∠XWZ = 22°, can ΔVZX and ΔWXZ be proven congruent by SAS? Why or why not?
Paul [167]

Answer: The ΔVZX and ΔWXZ are not congruent by SAS.

Explanation:

It is given that the VX = WZ = 40 cm and ∠ZVX = ∠XWZ = 22°.

Draw a figure as shown below,

According to the SAS rule of congruence, two triangles are congruent if two sides and their inclined angle is equal.

From the given figure it is easily noticed that in ΔVZX and ΔWXZ,

VX=WZ=40cm       (given)

\angle ZVX=\angle XWZ=22^{\circ}     (given)

XZ=XZ      (common side)

Since we have two sides and one angle is same. but we can not conclude that the ΔVZX and ΔWXZ are congruent by SAS, because the given angle is not the inclined angle of both equal sides.

Therefore, the  ΔVZX and ΔWXZ are not congruent by SAS.

4 0
3 years ago
Read 2 more answers
The graph of linear function f passes through the point (1, −9) and has a slope of −3. What is the zero of f?
ale4655 [162]
Zero of (f) equals -6
7 0
3 years ago
Someone help please, i cant solve this one :|
andrey2020 [161]

Answer:

i think its B

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What theorem shows that TPN ≅ TQM?
melisa1 [442]

Note: Consider the side of first triangle is TQ instead of TA.

Given:

Triangles TQM and TPN which share vertex T.

TQ\cong TP,TM\cong TN

To find:

The theorem which shows that \Delta TPN\cong TQM.

Solution:

In triangle TQM and TPN,

TQ\cong TP        [Given]

\angle QTM\cong \angle PTN         [Given]

TM\cong TN        [Given]

Since two sides and their including angle are congruent in both triangles, therefore both triangles are congruent by SAS postulate.

\Delta TPN\cong TQM              [SAS]

Therefore, the correct option is C.

5 0
3 years ago
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