Slope point form :
To put in slope point form, label any of the points as either X1,y1 and X and y, then plug in those values into the following equation form.
Y - y1 = m(X-X1)
But before, we must solve for the m value or slope.
M = y2-y1/x2-X1
M = 5/2 - -1/2 / -1/2 - 3/2.
M = 5/2 + 1/2 / -(1/2+3/2)
M = 6/2 / -(4/2)
M = 3/-2
Now we can place it in slope point and also in standard form of a line.
Y-y1 = m(X -X1)
Y - -1/2 = -3/2(X - 3/2)
Y + 1/2 = -3/2(X - 3/2)
This is in slope point form.
Y + 1/2 = -3/2x + 9/4
Y + 1/2 - 1/2 = -3/2x + 9/4 - 1/2
1/2 = 2/4
Y = -3/2x + 7/4
-3/2x = -6/4x
Y = -6/4x + 7/4
Y • 4 = 4( -6/4 X + 7/4)
4y = -6x + 7
4y + 6x = -6x + 6x +7
6x + 4y = 7
This is in standard form. If you have any questions of the steps just ask.
Plot and connect the points A (-4, -5), B (-2, -3), C (4, -3), D (6, -2), E (6, 6), F (-1, 6), G (-4, 2), and find the length of
eimsori [14]
Answer:
The length <u>EF</u> is 7 units.
Step-by-step explanation:
The length between the points E and F, using the plot below, is:
Therefore the <u>length EF is 7 units.</u>
I hope it helps you!
Answer:
D. y+4=2x
Step-by-step explanation:
-4 from both sides
y=2x-4
^ y-intercept (-4) same as on the graph
Answer:
402.07
Step-by-step explanation:
<span>Simplify For Example :Just as I can pull from a square (or second) root anything that I have two copies of, so also I can pull from a fourth root anything I've got four. </span>
