Solve for y. 8x+6y=10. Please show steps
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26% of all the employees attend night school
Step-by-step explanation:
The given is:
- Within a computer service company, 20 percent of the male employees and 30 percent of the female employees attend night school
- 40 percent of all employees are male
We need to find what percent of all the employees attend night school
Assume that the number of all employees is x
∵ The company has x employees
∵ 40 percent of all employees are male
- Find 40% of x
∵ 40% × x = × x = 0.4 x
∴ The number of the male employees is 0.4 x
- Subtract 0.4 x from x to find the number of the female employees
∵ The number of female employees = x - 0.4 x = 0.6 x
∴ The number of the female employees is 0.6 x
∵ 20 percent of the male employees attend night school
- Multiply 20% by 0.4 x to find the number of male employees
who attend night school
∴ The number of male who attend night school = 20% × 0.4 x
∴ The number of male who attend night school = × 0.4 x
∴ The number of male who attend night school = 0.08 x
∵ 30 percent of the female employees attend night school
- Multiply 30% by 0.6 x to find the number of female employees
who attend night school
∴ The number of female who attend night school = 30% × 0.6 x
∴ The number of male who attend night school = × 0.6 x
∴ The number of male who attend night school = 0.18 x
Add the number of male and female who attend night school
∵ 0.08 x + 0.18 x = 0.26 x
∴ The number of male and female who attend night school is 0.26 x
- Find the percentage of 0.26 x of x
∵ × 100% = 26%
∴ 26% of all the employees attend night school
26% of all the employees attend night school
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