Answer:
4(2e - 3)(3e + 1)
Step-by-step explanation:
Given
24e² - 28e - 12 ← factor out 4 from each term
= 4(6e² - 7e - 3) ← factor the quadratic
Consider the factors of the product of the e² term and the constant term which sum to give the coefficient of the e- term.
product = 6 × - 3 = - 18 and sum = - 7
The factors are - 9 and + 2
Use these factors to split the e- term
6e² - 9e + 2e - 3 ( factor the first/second and third/fourth terms )
= 3e(2e - 3) + 1 (2e - 3) ← factor out (2e - 3) from each term
= (2e - 3)(3e + 1)
Then
24e² - 28e - 12 = 4(2e - 3)(3e + 1) ← in factored form
The answer for "-2a + 3b" is 5.
To solve this equation, you must first find "a" and "b". A^3 times B^2 = 72. In this case, a = 2 (2*2*2 = 8) and b = 3 (3*3 = 9) since their outcomes multiplied together equal 72.
Now you fill in for "a" and "b". "-2*2 + 3*3" before adding you do all the multiplying, which leaves "-4 + 9". Combining like terms gives you 5.
I hope this helps!!
Answer:
D. 15 cm, 9 cm, 24 cm
Step-by-step explanation:
The three lengths that could be the lengths of the sides of a triangle, must satisfy the following condition;
---sum of any two smaller sides chosen must be equal to the third side.
Test option A : 6 cm + 11 cm = 17 cm ( 17 cm ≠ 23 cm)
Test option B: 10 cm + 15 cm = 25 cm (25 cm ≠ 24 cm)
Test option C: 6 cm + 6 cm = 12 cm (12 cm ≠ 22 cm)
Test option D: 15 cm + 9 cm = 24 cm (24 cm = 24 cm) ---correct option.
Thus, the three lengths that could be the lengths of the sides of a triangle are 15 cm, 9 cm, and 24 cm
Answer:
.13
Step-by-step explanation:
