<h2>
Speed with which it return to its initial level is 100 m/s</h2>
Explanation:
We have equation of motion v² = u² + 2as
Initial velocity, u = 100 m/s
Acceleration, a = -9.81 m/s²
Final velocity, v = ?
Displacement, s = 0 m
Substituting
v² = u² + 2as
v² = 100² + 2 x -9.81 x 0
v² = 100²
v = ±100 m/s
+100 m/s is initial velocity and -100 m/s is final velocity.
Speed with which it return to its initial level is 100 m/s
(1) The time of motion of the arrow is 0.25 s.
(2) The vertical height dropped by the arrow as it approaches the target is 0.31 m.
The given parameters:
- <em>Horizontal distance of the arrow, X = 20 m</em>
- <em>Horizontal speed of the arrow, v = 80 m/s</em>
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The time of motion of the arrow is calculated as follows;
The vertical height dropped by the arrow as it approaches the target is calculated as follows;
Learn more about time of motion of projectile here: brainly.com/question/1912408
Conductivity would be the property.
Answer:The lower the refractive index, the faster the velocity of light. Medium A has the smaller refractive index. Light will travel faster through medium A at a velocity equal to the speed of light divided by the refractive index.
Explanation:
THere ya go ! :)
