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Nataly_w [17]
3 years ago
7

A projectile is launched vertically at 100 m/s. If air resistance can be ignored, at what speed will it return to its initial le

vel?
Physics
2 answers:
eduard3 years ago
7 0
<h2>Speed with which it return to its initial level is 100 m/s</h2>

Explanation:

We have equation of motion v² = u² + 2as

Initial velocity, u = 100 m/s  

Acceleration, a = -9.81 m/s²  

Final velocity, v = ?

Displacement, s = 0 m  

Substituting  

v² = u² + 2as

v² = 100² + 2 x -9.81 x 0

v² = 100²

v = ±100 m/s

+100 m/s is initial velocity and -100 m/s is final velocity.

Speed with which it return to its initial level is 100 m/s

madreJ [45]3 years ago
6 0

Answer:

100 m/s

Explanation:

given,

vertical velocity of the projectile = 100 m/s

When the Projectile is launched vertically it will have two-component one is the vertical component and another is a horizontal component.

The horizontal component of velocity will remain constant.

The vertical component of the velocity will be zero at the highest point is zero and the second half motion of the projectile is the mirror of the first half movement of the projectile.

When the object reaches the initial level the velocity will be the same i.e. 100 m/s.

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Which one of the following is not equivalent to 2.50 miles?
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mi - km

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mi - yd

x = (2.50\,mi)\cdot \left(5280\,\frac{ft}{mi}\right) \cdot \left(\frac{1}{3}\,\frac{yd}{ft}  \right)

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mi - cm

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Choice C is not equivalent to 2.50 miles.

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Answer:

Check the explanation

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Kindly check the attached image below to see the step by step explanation to the question above.

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