Answer:
-2p - 1
Step-by-step explanation:
![\text{Combine like terms.}\\\\2+4p-6p-3\\\\4p-6p+2-3\\\\\boxed{-2p-1}\\\\\\\text{Hope this helps!}](https://tex.z-dn.net/?f=%5Ctext%7BCombine%20like%20terms.%7D%5C%5C%5C%5C2%2B4p-6p-3%5C%5C%5C%5C4p-6p%2B2-3%5C%5C%5C%5C%5Cboxed%7B-2p-1%7D%5C%5C%5C%5C%5C%5C%5Ctext%7BHope%20this%20helps%21%7D)
<em><u>Expression that represent the show the total cost for any number of rose bushes and tomato plant is:</u></em>
![Total\ cost = 5x + 2y](https://tex.z-dn.net/?f=Total%5C%20cost%20%3D%205x%20%2B%202y)
<em><u>Solution:</u></em>
Let "x" be the number of roses bush
Let "y" be the number of tomato plant
Cost of 1 rose bush = $ 5
Cost of 1 tomato plant = $ 2
To find: Expression that represent the show the total cost for any number of rose bushes and tomato plant
Total cost = number of roses bush x Cost of 1 rose bush + number of tomato plant x Cost of 1 tomato plant
![Total\ cost = x \times 5 + y \times 2\\\\Total\ cost = 5x + 2y](https://tex.z-dn.net/?f=Total%5C%20cost%20%3D%20x%20%5Ctimes%205%20%2B%20y%20%5Ctimes%202%5C%5C%5C%5CTotal%5C%20cost%20%3D%205x%20%2B%202y)
Thus the expression is found where, x and y are the number of rose bush and tomoato plant bought respectively
Answer:
<h2>326.56K</h2>
Step-by-step explanation:
Step one:
Given
V1=0.45L
P1=2.3atm
T1=60 °
V2=0.6L
P2=1.54atm
T2=?
Step two:
Required:
T2
Applying the partial gas formula
![\frac{P1V1}{T1}=\frac{P2V2}{T2}](https://tex.z-dn.net/?f=%5Cfrac%7BP1V1%7D%7BT1%7D%3D%5Cfrac%7BP2V2%7D%7BT2%7D)
![\frac{2.3*0.45}{60}=\frac{1.54*0.6}{T2}](https://tex.z-dn.net/?f=%5Cfrac%7B2.3%2A0.45%7D%7B60%7D%3D%5Cfrac%7B1.54%2A0.6%7D%7BT2%7D)
cross multiply we have
T2=(1.54*0.6*60)/2.3*0.45
T2=55.44/1.035
T2=53.56 °
in kelvin, we need to add 273
=273+53.56=326.56K
T2=326.56K
The new temperature of this gas (in K) is 326.56K
Answer:
-15x^2 + 36x + 7
Step-by-step explanation: