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KiRa [710]
2 years ago
13

What is the formula for surface area of a rectangular prism?

Mathematics
2 answers:
Sophie [7]2 years ago
7 0

Answer:

A=2(wl+hl+hw) hope this is helps you

Vesnalui [34]2 years ago
6 0

Answer:

A=2(wl+hl+hw)

Step-by-step explanation:

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Can y’all help me on question 20?!
denis23 [38]

Answer:

yes I can help you but ???

8 0
3 years ago
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Triangle XYZ was dilated by a scale factor of 2 to create triangle ACB and sin ∠X = 5 over 5 and 59 hundredths.
Vikentia [17]

The relationship between Traingle XYZ and ACB is that they are similar triangles. tanX = tanA = 5 over 2 and 5 tenths, where

  • AC = 2 x  XY
  • CB = 2 x  YZ

<h3>What is the dilation about?</h3>

Triangle XYZ was dilated by a scale factor of 2 to create triangle ACB, hence XYZ and ACB are similar triangles.

Angles Y and C are said to measure 90 degrees, and angles A and X are known to be congruent. Thus:

tanX = tanA = 5 over 2 and 5 tenths

AC = 2 x  XY

CB = 2 x  YZ

Another way to solve for it is by:

Note that Dilation of the triangle ΔXYZ was by a factor of "2".

Since m∠Y = m∠C = 90º   - given

ΔXYZ and ΔACB are said to be right triangles.

Since ∠X ≅ ∠A   - given

Then ∠X and ∠Z are  said to becomplementary angles

Since m∠Z = 90° - m∠X   -- given

Then ∠A and ∠B are said to be complementary angles

Since m∠B = 90° - m∠A  --- given

Then, ∠Z ≅ ∠B

Therefore ΔXYZ ∼ ΔACB are  similar triangles because it has its corresponding sides to be proportional and its corresponding angles to be congruent.

Note:

sin ∠X = 5/5.59

sin ∠X = YZ/XY

YZ = 5  seen in ΔXYZ

XZ = 5.59 seen in hypotenuse of ΔXYZ

Then one need to Calculate the length of one aspect of XY:

XY = √((5.59)2 - 52)

= 2.4996

Note CB/YZ = 2

CD = 2*YZ = 2 x 5

= 10

AC/XY = 2

AC = 2* XY

= 2 x 2.4996

= 4.999

Learn more about dilation from:

brainly.com/question/27517432

#SPJ1

7 0
2 years ago
Which is the graph of y= x-5-1?
tamaranim1 [39]

Answer:

None of them

Step-by-step explanation:

Because i can't see the graph

6 0
3 years ago
Read 2 more answers
A 6m ladder leans against a wall. The bottom of the ladder is 1.3m from the wall at time =0sec and slides away from the wall at
icang [17]

Answer:

- 0.100

Step-by-step explanation:

Length of the ladder,  H = 6 m

Distance at the bottom from the wall, B = 1.3 m

Let the distance of top of the ladder from the bottom at the wall is P

Thus,

from  Pythagoras theorem,

B² + P² = H²    .

or

B² + P² = 6²          ..............(1)      [Since length of the ladder remains constant]

at B = 1.3 m

1.3² + P² = 6²

or

P² = 36 - 1.69

or

P² = 34.31

or

P = 5.857

Now,

differentiating (1)

2B(\frac{dB}{dt})+2P(\frac{dP}{dt})=0

at t = 2 seconds

change in B = 0.3 × 2= 0.6 ft

Thus,

at 2 seconds

B = 1.3 + 0.6 = 1.9 m

therefore,

1.9² + P² = 6²

or

P = 5.69 m

on substituting the given values,

2(1.9)(0.3) + 2(5.69) × (\frac{dP}{dt}) = 0

or

1.14 + 11.38 × (\frac{dP}{dt}) = 0

or

11.38 × (\frac{dP}{dt}) = - 1.14

or

(\frac{dP}{dt}) = - 0.100

here, negative sign means that the velocity is in downward direction as upward is positive

5 0
3 years ago
ILL GIVE BRAINLIEST PLEASE HELP ASAP PLS
postnew [5]

Answer:

5/12 of rain came, or 10 inches

Step-by-step explanation:

complete rain be 1

then, =1-(1/4+1/3)

=1-(3+4/12) take lcm

=1-7/12

=12-7/12 again lcm

= 5/12

or

1/4 of 24 inches means 1/4×24= 6 inches

1/3 of 24 inches, then 1/3×24= 8 inches

therefore, rest of the months get

= 24-(6+8)

=24-14

=10 inches

7 0
3 years ago
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