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VikaD [51]
3 years ago
9

If 50% of an item is $34.00, what is the original price? ​

Mathematics
2 answers:
masya89 [10]3 years ago
4 0

Answer:

68.00

Step-by-step explanation:

Arlecino [84]3 years ago
3 0

Answer:

Step-by-step explanation: take it times two to get the answer! 34 times 2= 68. So the answer is 68.00 dollars!

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Each school bus going on the field trip holds 36 students and 4 adults.There are 6 filled buses on the field trip.How many peopl
Dvinal [7]

Hello there

36+4=40 people in one bus

In 6 buses how many people?

40•6=240 people are going on the field trip

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6 0
3 years ago
Marking as brainliest!!!!
7nadin3 [17]

Answer:

The answer to your question is: Letter A

Step-by-step explanation:

Data

M (-6, 7)

E (4, 11)

r = 1 / 3

Formula

x = \frac{x1 + rx2}{1 + r}

y = \frac{y1 + ry2}{1 + r}

x = \frac{-6 + (1/3)(11)}{(4/3)} = \frac{-6 + (4/3)}{(4/3)}  = \frac{-18 + 4}{4} = \frac{-14}{4}  = \frac{-7}{2}

y = \frac{7 + (1/3)(11)}{4/3} = \frac{7 + (11/3)}{(4/3)} = \frac{21+ 11}{4}  = \frac{32}{4} = 8

5 0
2 years ago
Which expression is equivalent to the value of 144?
9966 [12]

Answer:

100+44

Step-by-step explanation:

3 0
2 years ago
I need answers for the questions in the picture
Mama L [17]
Answer: a. gregory b. linus

step by step explanation:
3 0
2 years ago
What is a cubic polynomial function in standard form with zeroes 1, –2, and 2?
Lisa [10]
Starting off with the polynomial in standard form would be extremely difficult, but we can construct one fairly easily with the zeroes we've been given.

We know from the given zeroes that our function has the value 0 when x = 1, x = -2, and x = 2. Manipulating each equation, we can rewrite them as x - 1 = 0, x + 2 = 0, and x - 2 = 0. To construct our polynomial, we simply use all three of the expressions on the left side of the equation as factors and multiply them together, obtaining:

(x-1)(x+2)(x-2)=0

Notice that we can easily obtain each our three zeroes by dividing both sides by the two other factors. From here, we just need to expand the left-hand side of the equation. I'll show the work required here:

(x-1)(x+2)(x-2)=0\\
\big[(x-1)x+(x-1)2\big](x-2)=0\\
(x^2-x+2x-2)(x-2)=0\\
(x^2+x-2)(x-2)=0\\
(x^2+x-2)x-(x^2+x-2)2=0\\
x^3+x^2-2x-(2x^2+2x-4)=0\\
x^3+x^2-2x-2x^2-2x+4=0\\
x^3+(x^2-2x^2)+(-2x-2x)+4=0\\
x^3-x^2-4x+4=0\\

So, in standard form, our cubic polynomial would be x^3-x^2-4x+4
3 0
3 years ago
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