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3 years ago

If 50% of an item is $34.00, what is the original price?

Mathematics

2 answers:

masya89 [10]3 years ago

4 0

Answer:

68.00

Step-by-step explanation:

Arlecino [84]3 years ago

3 0

Answer:

Step-by-step explanation: take it times two to get the answer! 34 times 2= 68. So the answer is 68.00 dollars!

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A shirt marked $320.00 was sold at a discount of 5%. What was the selling price?

Mashcka [7]

Answer:

304

Step by step:

Using your calculator 5% of 320 is 16.

Since it was a discount, you subtract 16 since you're marking it down.

320-16=304

304 is your answer

How do I know? Well, there it takes 20+20+20+20+20 to equal a hundred. We can do this same math for this problem. 16 x 20 is 320

3 0

3 years ago

Read 2 more answers

Plz Help your fav. Marshmello i wasn' t,,,,, xx born yesterday.

Mama L [17]

Answer:

x=9

Step-by-step explanation:

first you would distribute the -4 and the -12

-24x-12=-12x-120

Then you would add 120 to both sides

-24x+108=-12x

Then add 24x to both sides

108=12x

Then divide both sides by 12

x=9

7 0

3 years ago

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The measure of an interor angle of a regular polygon is given. Find the number of sides in the polygon.

EleoNora [17]

Let side be n

$\\ \sf\longmapsto 120n=(n-2)180$

$\\ \sf\longmapsto 120n=180n-360$

$\\ \sf\longmapsto -60n=-360$

$\\ \sf\longmapsto n=6$

$\\ \sf\longmapsto 160n=(n-2)180$

$\\ \sf\longmapsto 160n=180n-240$

$\\ \sf\longmapsto -20n=-240$

$\\ \sf\longmapsto n=12$

$\\ \sf\longmapsto 144n=(n-2)180$

$\\ \sf\longmapsto 144n=180n-360$

$\\ \sf\longmapsto -36n=-360$

$\\ \sf\longmapsto n=10$

6 0

3 years ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$