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alisha [4.7K]
3 years ago
12

HELP WITH 20 PLEASE!

Mathematics
1 answer:
agasfer [191]3 years ago
7 0
Divide the circumference by 2, then square that number 
What you are doing is dividing the diameter by 2, getting the radius then squaring which is the formula pi r^2
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Find x. <br> A. 13.7 <br> B. 5.5<br> C. 11.8<br> D. 9.6
Goryan [66]
C. 11.8 ( remember a2+b2=C2 )
4 0
3 years ago
Sin∅=√3-1/2 find approximate value of sec∅(sec∅+tan∅)/1+tan²∅​
Neko [114]

Answer:

The approximate value of f(\theta) = \frac{\sec \theta \cdot (\sec \theta+\tan \theta)}{1+\tan^{2}\theta} is 1.366.

Step-by-step explanation:

Let f(\theta) = \frac{\sec \theta \cdot (\sec \theta+\tan \theta)}{1+\tan^{2}\theta}, we proceed to simplify the formula until a form based exclusively in sines and cosines is found. From Trigonometry, we shall use the following identities:

\sec \theta = \frac{1}{\cos \theta} (1)

\tan\theta = \frac{\sin\theta}{\cos \theta} (2)

\cos^{2}+\sin^{2} = 1 (3)

Then, we simplify the given formula:

f(\theta) = \frac{\left(\frac{1}{\cos \theta} \right)\cdot \left(\frac{1}{\cos \theta}+\frac{\sin \theta}{\cos \theta}\right) }{1+\frac{\sin^{2}\theta}{\cos^{2}\theta} }

f(\theta) = \frac{\left(\frac{1}{\cos^{2} \theta} \right)\cdot (1+\sin \theta)}{\frac{\sin^{2}\theta + \cos^2{\theta}}{\cos^{2}\theta} }

f(\theta) = \frac{\left(\frac{1}{\cos^{2}\theta}\right)\cdot (1+\sin \theta)}{\frac{1}{\cos^{2}\theta} }

f(\theta) = 1+\sin \theta

If we know that \sin \theta =\frac{\sqrt{3}-1}{2}, then the approximate value of the given function is:

f(\theta) = 1 +\frac{\sqrt{3}-1}{2}

f(\theta) = \frac{\sqrt{3}+1}{2}

f(\theta) \approx 1.366

5 0
3 years ago
PLEASE HELP ME!!!!
coldgirl [10]
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3 years ago
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